Hey all,
Another creative question: is it possible to do something like this to type
define a pointer to a specific type of function:
typedef bool (*)(std::string::const_iterator,
std::string::const_iterator) ItCompare;
And if so, how? The above example does not work, btw, I'm just wondering if
there is a way.
- JFA1
3  3897 
Try
typedef bool (*ItCompare)
(
std::string::const_iterator,
std::string::const_iterator
);
James Aguilar wrote: Hey all,
Another creative question: is it possible to do something like this to type
define a pointer to a specific type of function:
typedef bool (*)(std::string::const_iterator,
std::string::const_iterator) ItCompare;
And if so, how? The above example does not work, btw, I'm just wondering if
there is a way.
- JFA1
"James Aguilar" <jf**@cec.wustl.edu> wrote in message
news:d2**********@newsreader.wustl.edu... Hey all,
Another creative question: is it possible to do something like this to
type define a pointer to a specific type of function:
typedef bool (*)(std::string::const_iterator,
std::string::const_iterator) ItCompare;
And if so, how? The above example does not work, btw, I'm just wondering
if there is a way.
I solved this one on my own just after asking. For those who want to know,
the syntax is like this:
typedef bool (*ItCompare)(std::string::const_iterator,
std::string::const_iterator);
James Aguilar wrote: Hey all,
Another creative question: is it possible to do something like this to type
define a pointer to a specific type of function:
typedef bool (*)(std::string::const_iterator,
std::string::const_iterator) ItCompare;
And if so, how? The above example does not work, btw, I'm just wondering if
there is a way.
As with other typedefs for pointers to functions, the new type alias
should be together with the *:
typedef bool (*ItCompare)(std::string::const_iterator,
std::string::const_iterator);
--
Ioannis Vranos http://www23.brinkster.com/noicys This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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