xlc - A template dependent name that is a type must be qualified with "typename"

[pervinder]

Hi,
I get an error on line #3 while compiling the program segment on aix
(xlc - va6)
While this warning is not seen with gcc

"test.cpp" line 200.18: 1540-0152 (W) A template dependent name that
is a type must be qualified with "typename".
#1 template<class KeyType,
class ValueType, ....>
#2 class Iterator;
#3 friend class Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

Does anyone has a hint for this behaviour ?

R/s
pervinder

[Malte Starostik]

pervinder schrieb:

Hi,
I get an error on line #3 while compiling the program segment on aix
(xlc - va6)
While this warning is not seen with gcc
gcc has been warning about this since version 3.0. Anything before that
is totally outdated (current version is 3.4.3 and 4.0 is due soon...)
"test.cpp" line 200.18: 1540-0152 (W) A template dependent name that
is a type must be qualified with "typename".
#1 template<class KeyType,
class ValueType, ....>
#2 class Iterator;
#3 friend class Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

Does anyone has a hint for this behaviour ?

As the warning says, types that depend on a template parameter must be
qualified with the typename keyword:

friend class typename Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

This way, you tell the compiler that
Cpp_SortedList<KeyType,ValueType,.....> :: Iterator is a type and not a
data member or member function.

template< typename T >
struct Foo
{
std::vector< int >::iterator it1;
// fine, std::vector< int > does not depend on T
std::vector< T >::iterator it2;
// error, std::vector< T > depends on T
typename std::vector< T >::iterator it3;
// fine, typename used
};

Cheers,
Malte

[Rolf Magnus]

Malte Starostik wrote:

pervinder schrieb:

Hi,
I get an error on line #3 while compiling the program segment on aix
(xlc - va6)
While this warning is not seen with gcc

gcc has been warning about this since version 3.0. Anything before that
is totally outdated (current version is 3.4.3 and 4.0 is due soon...)

"test.cpp" line 200.18: 1540-0152 (W) A template dependent name that
is a type must be qualified with "typename".
#1 template<class KeyType,
class ValueType, ....>
#2 class Iterator;
#3 friend class Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

Does anyone has a hint for this behaviour ?

As the warning says, types that depend on a template parameter must be
qualified with the typename keyword:

friend class typename Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

....although it looks strange in this particular place. I mean, you already
said "class", so what could that class be, other than a type? I guess it's
just needed here to make the rules simpler.

[pervinder]

The typename did not work, compiler generates the same warnings again
The Cpp_SortedList is defined as below :-

template<class KeyType,
class ValueType,
class LessThan = less<KeyType>,
class MemoryBase = Cpp_CachedSmallObject

class Cpp_SortedList : public MemoryBase {
protected: ,,,
,,,,,,,,,,,,,,,,,
}

R/s
pervinder

Rolf Magnus <ra******@t-online.de> wrote in message news:<d1*************@news.t-online.com>... Malte Starostik wrote:

pervinder schrieb:

Hi,
I get an error on line #3 while compiling the program segment on aix
(xlc - va6)
While this warning is not seen with gcc

gcc has been warning about this since version 3.0. Anything before that
is totally outdated (current version is 3.4.3 and 4.0 is due soon...)

"test.cpp" line 200.18: 1540-0152 (W) A template dependent name that
is a type must be qualified with "typename".
#1 template<class KeyType,
class ValueType, ....>
#2 class Iterator;
#3 friend class Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

Does anyone has a hint for this behaviour ?

As the warning says, types that depend on a template parameter must be
qualified with the typename keyword:

friend class typename Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

...although it looks strange in this particular place. I mean, you already
said "class", so what could that class be, other than a type? I guess it's
just needed here to make the rules simpler.

[Malte Starostik]

pervinder schrieb:

The typename did not work, compiler generates the same warnings again
The Cpp_SortedList is defined as below :-

template<class KeyType,
class ValueType,
class LessThan = less<KeyType>,
class MemoryBase = Cpp_CachedSmallObject

> class Cpp_SortedList : public MemoryBase {
protected: ,,,
,,,,,,,,,,,,,,,,,
}

friend class typename Cpp_SortedList<KeyType,ValueType,.....> :: Iterator;

Only now I see it's a friend declaration...how is Cpp_SortedList< ...::Iterator declared? If it's a typedef you can't befriend it :-(

Any chance you could provide a minimal but complete example that
produces the problem?

Cheers,
Malte