operator <<=

[def5]

Hi,
what make this <<= operator ?

Code:
UCHAR x = 0 ;
x <<=6 ;

Thanks

[Brian Schelde]

<de**@pobox.sk> wrote in message
news:11*********************@g14g2000cwa.googlegro ups.com...

what make this <<= operator ? Its like when you write x += 2 is the same as x = x + 2

Code:
UCHAR x = 0 ;
x <<=6 ;

It is the same as writing: x = x << 6;
But its easier to optimize for the compiler

[shabbir]

<< operator is a leftshift operator and <<= combines the left shift
operator with the assignment operator

[Richard Cavell]

On 7/3/05 7:22 PM, de**@pobox.sk wrote:

Hi,
what make this <<= operator ?

Code:
UCHAR x = 0 ;
x <<=6 ;

Shift x to the left by 6 bits. In this case, x will still equal zero.

[Ron Natalie]

Brian Schelde wrote:

It is the same as writing: x = x << 6;
But its easier to optimize for the compiler

The second statement is extremely dubious. I can't
imagine any compiler that would care.

[Richard Cavell]

On 7/3/05 10:57 PM, Ron Natalie wrote:

The second statement is extremely dubious. I can't
imagine any compiler that would care.

Perhaps it's easier for the programmer to conceptualise. For example,
it makes clear that the source and destination operand are the same, and
that there is something transitive about the variable. (So if your code
is full of const things that are used on the right hand side of an
assignment, this ain't a const).