question on try/catch

[xuatla]

Hi,

I tried the following code about try/catch (from cplusplus.com)

// exceptions
#include <ciostream>
using namespace std;

int main () {
char myarray[10];
try
{
for (int n=0; n<=10; n++)
{
if (n>9) throw "Out of range";
myarray[n]='z';
}
}
catch (char * str)
{
cout << "Exception: " << str << endl;
}
return 0;
}

It's expected to give "Exception: Out of range".
but i complied in g++ 3.3.3. and run it, the output is "Aborted".

Anyone help me to explain what's wrong here? or normal?

Thanks a lot!

xuatla

[Phil Staite]

xuatla wrote:

Hi,

I tried the following code about try/catch (from cplusplus.com)

// exceptions
#include <ciostream>
using namespace std;

int main () {
char myarray[10];
try
{
for (int n=0; n<=10; n++)
{
if (n>9) throw "Out of range";
myarray[n]='z';
}
}
catch (char * str)
{
cout << "Exception: " << str << endl;
}
return 0;
}

It's expected to give "Exception: Out of range".
but i complied in g++ 3.3.3. and run it, the output is "Aborted".

Anyone help me to explain what's wrong here? or normal?

Try making the catch:

catch( const char* str )

I don't use g++ much, maybe it considers literal strings such as "Out of
range" to be const char*. Therefore it wouldn't match/catch a
non-const...

[modemer]

"xuatla" <xu****@gmail.com> ??????:d0**********@daisy.noc.ucla.edu...

Hi,

I tried the following code about try/catch (from cplusplus.com)

// exceptions
#include <ciostream>
using namespace std;

int main () {
char myarray[10];
try
{
for (int n=0; n<=10; n++)
{
if (n>9) throw "Out of range";
myarray[n]='z';
}
}
catch (char * str)
should be:
catch (char const *str)
{
cout << "Exception: " << str << endl;
}
return 0;
}

It's expected to give "Exception: Out of range".
but i complied in g++ 3.3.3. and run it, the output is "Aborted".

Anyone help me to explain what's wrong here? or normal?

Thanks a lot!

xuatla

[Rolf Magnus]

xuatla wrote:

Hi,

I tried the following code about try/catch (from cplusplus.com)

// exceptions
#include <ciostream>
using namespace std;

int main () {
char myarray[10];
try
{
for (int n=0; n<=10; n++)
{
if (n>9) throw "Out of range";
myarray[n]='z';
}
}
catch (char * str)
{
cout << "Exception: " << str << endl;
}
return 0;
}

It's expected to give "Exception: Out of range".
but i complied in g++ 3.3.3. and run it, the output is "Aborted".

Anyone help me to explain what's wrong here? or normal?

You're not catching the exception you threw. "Out of range" is of type
const char[13], which gets converted to const char* before being thrown. But
you're not catching const char*, and therefore the exception gets out. The
result is correct (std::abort() being called).

[Andrew Koenig]

"xuatla" <xu****@gmail.com> wrote in message
news:d0**********@daisy.noc.ucla.edu...

#include <ciostream>
using namespace std;

int main () {
char myarray[10];
try
{
for (int n=0; n<=10; n++)
{
if (n>9) throw "Out of range";
myarray[n]='z';
}
}
catch (char * str)
{
cout << "Exception: " << str << endl;
}
return 0;
}

It's expected to give "Exception: Out of range".
but i complied in g++ 3.3.3. and run it, the output is "Aborted".

Anyone help me to explain what's wrong here? or normal?

What happens if you change

catch (char * str)

to

catch (const char * str)

?