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Can I print elements of a simple matrix with out manual nested loop?

Suppose I have a matrix M x N dimension.
Normally, to print all of the elements in the matrix. I write the
following codes:

Suppose M = 5, N = 4:

for(int j=0; j<5; ++j) {
for(int k=0; k<4; ++k) {
cout << matrix[M][N] << " ";
cout << endl;

If my matrix class has method for return number of dimension and
dimension size such as:

numDimension(matrix); // return 2 becase the matrix has M x N = 2

sizeDimension(0); // return 5 -- size of M
sizeDimension(1); // return 4 -- size of N

How to write some code that print all element of the matrix with out
code nested loops by hand?


Jul 23 '05 #1
1 1560
How to write some code that print all element of the matrix with out
code nested loops by hand?

You can just create a double loop, where the outermost loop iterates of
the number of dimensions, while the inner loop goes from 0 to

However, you will need to decide yourself how to lay out a -- say --
5-dimensional matrix in the 2-dimensional "cout space".

You will also need to calculate your indices yourself somehow, but your
already probably have your "matrix" class to help you out here, don't
you? (Or how does it otherwise implement matrix[n][m] in a 2-dim.
matrix, and say matrix[n][m][p][q][r] in a 5-dimensional one?) Along the
way, you will need to maintain som state variables, to keep track of
(and temporarily remember) indices you are starting at in each
direction. Some stack- or list-like functionality probably; hint:

Another way to solve this latter is considering some kind of recursive

Jul 23 '05 #2

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