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# Backward processing of an array

 P: n/a Can someone help me with this program? Please! Create an array named fun[] of 20 integers. Initialize it to the expression: fun[i] = 7 * i * i - 4 * i - 500 where i is the index to the array. Process the array backward and output only those elements whose values are positive and within a range as specified by the user. Thank you. Jul 23 '05 #1
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 P: n/a "sunrise" wrote in message news:e2*************************@posting.google.co m... Can someone help me with this program? Please! Create an array named fun[] of 20 integers. Initialize it to the expression: fun[i] = 7 * i * i - 4 * i - 500 where i is the index to the array. Process the array backward and output only those elements whose values are positive and within a range as specified by the user. Thank you. This sounds like homework. I believe your answer lies in the FAQ (http://www.parashift.com/c++-faq-lite/) under section 5, questions 2 and following. -- David Hilsee Jul 23 '05 #2

 P: n/a "sunrise" wrote in message news:e2*************************@posting.google.co m... Can someone help me with this program? Please! Certainly, as soon as you show us your program. You weren't expecting someone to write it for you, were you? Create an array named fun[] of 20 integers. Initialize it to the expression: fun[i] = 7 * i * i - 4 * i - 500 Well, there's one line already written for you. All you need to do is add the semicolon. where i is the index to the array. Process Does 'process' mean the storing of the values, retrieving the values, or both? the array backward Hint: start with the largest index, and count down to zero. and output only those elements whose values are positive and within a range as specified by the user. Hint: if(fun[i] > 0 && fun[i] >= lowest && fun[i] <= highest) printf("%d\n", array[i]); Thank you. You're welcome. -Mike Jul 23 '05 #3

 P: n/a sunrise wrote: Can someone help me with this program? Please! Just do it a step at a time. 1. > Create an array named fun[] of 20 integers. 2. > Initialize it to the expression: fun[i] = 7 * i * i - 4 * i - 500 where i is the index to the array. 4. > Process the array backward and output only those elements whose values are positive and 3. > within a range as specified by the user. -- Ioannis Vranos http://www23.brinkster.com/noicys Jul 23 '05 #4

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