Abhijit Bhadra wrote:
Hi ,
In C++ , I have some files as per their date of creation .
The files are in the form of
maple01012005.log
maple01142005.log
maple01202005.log
sample01182005.log
sample01192005.log
sample01202004.log
sample01202005.log
ample012020051517.log
sample012020051522.log
So the general format of files are <file_name>ddmmyyyyhhmm .
Where hhmm are optional .
Now those file names I put into a list and calling sort() command .
sort obviously will not sort in the form of date .
Can anyone help me to implement sort function .
You made yourself a lot of troubles by choosing a hard to parse
format for including the time stamp into the file name. If
possible change that first
eg. sample012020052004.log
is that file sample.log created at the day = 01
month = 20
year = 2005
hour = 20
minute = 04
or is that file
sample0120.log created at the day = 20
month = 05
year = 2004
In any case. Every sort algorithm needs to compare 2 entries,
to decide which one is less.
In your case this means: locate the date/time stamp, extract
that and base your comparison on that instead of the full
filename.
So your first goal is: to locate and extract the time/date stamp.
Once you have that and you still have problems inserting that
information into a sorting algorithm, come back and ask for
help again. But for this, you definitly need the date/time stamp
alone.
--
Karl Heinz Buchegger
kb******@gascad.at 
