Variables in (and out) of namespaces

[K Campbell]

Say I have the code in a program below:

namespace c_name
{
int j;
}

int main(int argc, char* argv[])
{
using namespace std;
int j;
cout<<"Hello, World!"<<endl;
using namespace c_name;
j = 5;
}

I was wondering how I could access j (the not the one in c_name).
Any tips?
Kieran

[Victor Bazarov]

"K Campbell" <ki****@cyrocom.co.uk> wrote...

Say I have the code in a program below:

namespace c_name
{
int j;
}

int main(int argc, char* argv[])
{
using namespace std;
int j;
cout<<"Hello, World!"<<endl;
using namespace c_name;
j = 5;
}

I was wondering how I could access j (the not the one in c_name).
Any tips?

There is no way. A tip: don't use 'using', use 'c_name::'.

V

[Siemel Naran]

"K Campbell" <ki****@cyrocom.co.uk> wrote in message

namespace c_name
{
int j;
}

int main(int argc, char* argv[])
{
using namespace std;
int j;
cout<<"Hello, World!"<<endl;
using namespace c_name;
j = 5;
}

I was wondering how I could access j (the not the one in c_name).
Any tips?

Does ::j work?

[Victor Bazarov]

"Siemel Naran" <Si*********@REMOVE.att.net> wrote...

"K Campbell" <ki****@cyrocom.co.uk> wrote in message

namespace c_name
{
int j;
}

int main(int argc, char* argv[])
{
using namespace std;
int j;
cout<<"Hello, World!"<<endl;
using namespace c_name;
j = 5;
}

I was wondering how I could access j (the not the one in c_name).
Any tips?

Does ::j work?

Why would it? There is no j in the global namespace.

V

[Siemel Naran]

"Victor Bazarov" <v.********@comAcast.net> wrote in message
news:_vvsd.716685

"Siemel Naran" <Si*********@REMOVE.att.net> wrote...

int main(int argc, char* argv[])
{
using namespace std;
int j;
cout<<"Hello, World!"<<endl;
using namespace c_name;
j = 5;
}

I was wondering how I could access j (the not the one in c_name).
Any tips?

Does ::j work?

Why would it? There is no j in the global namespace.

Yes, I tried it and it gives a compile error.