operator new & delete overriding in template

[Cheng Mo]

When overriding operator new & delte of one class, the method is
implicitly declared as static. However, overriding operator new & delete
of template cannot be static.The compiler says cannot declare the
function a static linkage. Why?
C++ is so complex and so many situation should be considered.

[Victor Bazarov]

"Cheng Mo" <mo******@nospam.nospam> wrote...

When overriding operator new & delte of one class, the method is
implicitly declared as static. However, overriding operator new & delete
of template cannot be static.The compiler says cannot declare the function
a static linkage. Why?
C++ is so complex and so many situation should be considered.

Read the FAQ 5.8.

This:
--------------------
#include <typeinfo>
#include <iostream>

template<class T>
class A {
public:
A(int) {}
void * operator new(size_t s) {
std::cout << "new A<" << typeid(T).name() << ">\n";
return malloc(s); }
void operator delete(void* p, size_t s) { free(p); }
};

int main()
{
A<int> *paint = new A<int>(42);
}
--------------------
compiles just fine (as it should)

V

[Cheng Mo]

I know that the compilation and execution is OK.
What I want to konw is that why member functions in template cannot be
declared as static.

Victor Bazarov wrote:

"Cheng Mo" <mo******@nospam.nospam> wrote...

When overriding operator new & delte of one class, the method is
implicitly declared as static. However, overriding operator new & delete
of template cannot be static.The compiler says cannot declare the function
a static linkage. Why?
C++ is so complex and so many situation should be considered.

Read the FAQ 5.8.

This:
--------------------
#include <typeinfo>
#include <iostream>

template<class T>
class A {
public:
A(int) {}
void * operator new(size_t s) {
std::cout << "new A<" << typeid(T).name() << ">\n";
return malloc(s); }
void operator delete(void* p, size_t s) { free(p); }
};

int main()
{
A<int> *paint = new A<int>(42);
}
--------------------
compiles just fine (as it should)

V

[Victor Bazarov]

Cheng Mo wrote:

I know that the compilation and execution is OK.
What I want to konw is that why member functions in template cannot be
declared as static.
I don't understand the question, probably. Overloaded operators 'new' and
'delete' shall not be _declared_ static, but they _are_ static, as you
noted in your post. Any other function _can_ be declared static, unless
it's a constructor, the destructor, operator= (and some other operators).

What makes you think that members of templates can't be static?

template<class T> class HasStatic {
public:
static void foo(); // here it is, a static member
};

And, please, don't top-post, OK? Thanks!

Victor Bazarov wrote:

"Cheng Mo" <mo******@nospam.nospam> wrote...

When overriding operator new & delte of one class, the method is
implicitly declared as static. However, overriding operator new &
delete of template cannot be static.The compiler says cannot declare
the function a static linkage. Why?
C++ is so complex and so many situation should be considered.

Read the FAQ 5.8.

This:
--------------------
#include <typeinfo>
#include <iostream>

template<class T>
class A {
public:
A(int) {}
void * operator new(size_t s) {
std::cout << "new A<" << typeid(T).name() << ">\n";
return malloc(s); }
void operator delete(void* p, size_t s) { free(p); }
};

int main()
{
A<int> *paint = new A<int>(42);
}
--------------------
compiles just fine (as it should)

V

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