C++ and C difference

[EvanB]

How could I convert the following C code into a C++ equivalent? I have no
idea how to do the formatting in C++.

void OutputPay(Employee *emp){
printf(“%06X %8.3f\n”,emp->DID, emp->DPay);
emp->DPaid = TRUE;
}

Thanks in advance,
Evan

[Victor Bazarov]

EvanB wrote:

How could I convert the following C code into a C++ equivalent? I have no
idea how to do the formatting in C++.

void OutputPay(Employee *emp){
printf(“%06X %8.3f\n”,emp->DID, emp->DPay);
emp->DPaid = TRUE;
}

RTFM on "iostream manipulators". Pay attention to 'hex' format flag,
'setfill' manipulator, 'setw' manipulator, 'fixed' format flag, and
'setprecision' manipulator.

V

[Mike Wahler]

"EvanB" <ed******@ucdavis.edu> wrote in message
news:78******************************@localhost.ta lkaboutprogramming.com...

How could I convert the following C code into a C++ equivalent?
Your code qualifies as "C++ code".
I have no
idea how to do the formatting in C++.

void OutputPay(Employee *emp){
printf(“%06X %8.3f\n”,emp->DID, emp->DPay);
emp->DPaid = TRUE;
}

C++ introduces 'IOStreams', 'stream manipulators',
'stream format flags', etc.:

void OutputPay(Employee *emp)
{
std::cout << std::hex
<< std::setfill('0')
<< std::setw(6}
<< emp->DID
<< std::dec
<< std::fixed
<< std::setprecision(3)
<< std::setw(11)
<< emp-DPay);

emp->DPaid = true; /* 'true' is a C++ keyword */
}

See the declarations of the <ios> and <iomanip> headers.

Recommended books:
http://www.josuttis.com/libbook/
http://www.langer.camelot.de/iostreams.html

-Mike

[Mike Wahler]

"Mike Wahler" <mk******@mkwahler.net> wrote in message
news:al*****************@newsread1.news.pas.earthl ink.net...

I left out one item:

void OutputPay(Employee *emp)
{
std::cout << std::hex
<< std::setfill('0')
<< std::setw(6}
<< emp->DID
<< std::dec
<< std::setfill(' ')
<< std::fixed
<< std::setprecision(3)
<< std::setw(11)
<< emp-DPay);

emp->DPaid = true; /* 'true' is a C++ keyword */
}

(All formatting changes applied to a stream remain in effect
until specifically changed again -- except 'setw()', which
must be invoked each time a field width need be specified).

-Mike

[Vyacheslav Kononenko]

EvanB wrote:

How could I convert the following C code into a C++ equivalent? I have no
idea how to do the formatting in C++.

void OutputPay(Employee *emp){
printf(“%06X %8.3f\n”,emp->DID, emp->DPay);
emp->DPaid = TRUE;
}

Thanks in advance,
Evan

void Employee::OutputPay(){
std::cout << boost::format(“%06X %8.3f\n”) % DID % DPay;
DPaid = true;
}

and variations

--
Regards,
Slava

[Howard]

"Vyacheslav Kononenko" <vy********@NOkononenkoSPAM.net> wrote in message
news:Fx*****************@mencken.net.nih.gov...

EvanB wrote:

How could I convert the following C code into a C++ equivalent? I have no
idea how to do the formatting in C++.

void OutputPay(Employee *emp){
printf(%06X %8.3f\n,emp->DID, emp->DPay);
emp->DPaid = TRUE;
}

Thanks in advance,
Evan

void Employee::OutputPay(){
std::cout << boost::format(%06X %8.3f\n) % DID % DPay;
DPaid = true;
}

and variations

--
Regards,
Slava

Technically speaking, that's not standard C++, is it? Isn't the Boost
library third-party software? (I don't see anything related to Boost in my
libraries, at least.)

Also, isn't that a typo? I think you meant to use the << operators before
DID and DPay, right?

-Howard

[JKop]

Howard posted:

"Vyacheslav Kononenko" <vy********@NOkononenkoSPAM.net> wrote in
message news:Fx*****************@mencken.net.nih.gov...

EvanB wrote:

How could I convert the following C code into a C++ equivalent? I
have no idea how to do the formatting in C++.

void OutputPay(Employee *emp){
printf(%06X %8.3f\n,emp->DID, emp->DPay);
emp->DPaid = TRUE; }

Thanks in advance,
Evan

void Employee::OutputPay(){
std::cout << boost::format(%06X %8.3f\n) % DID % DPay;
DPaid = true;
}

and variations

--
Regards,
Slava

Technically speaking, that's not standard C++, is it? Isn't the Boost
library third-party software? (I don't see anything related to Boost
in my libraries, at least.)

Also, isn't that a typo? I think you meant to use the << operators
before DID and DPay, right?

-Howard

Then copy-paste the boost file. Now it's Standard C++!
( or would that be piracy? ;-P )
-JKop

[EvanB]

Awesome, thanks. That helps tremendously :) The spacing operations were
throwing me off in C++.

Evan

[David Hilsee]

"Howard" <al*****@hotmail.com> wrote in message
news:0a*********************@bgtnsc04-news.ops.worldnet.att.net...

"Vyacheslav Kononenko" <vy********@NOkononenkoSPAM.net> wrote in message
news:Fx*****************@mencken.net.nih.gov...

EvanB wrote:

How could I convert the following C code into a C++ equivalent? I have no idea how to do the formatting in C++.

void OutputPay(Employee *emp){
printf(%06X %8.3f\n,emp->DID, emp->DPay);
emp->DPaid = TRUE;
}

Thanks in advance,
Evan

void Employee::OutputPay(){
std::cout << boost::format(%06X %8.3f\n) % DID % DPay;
DPaid = true;
}

and variations

--
Regards,
Slava

Technically speaking, that's not standard C++, is it? Isn't the Boost
library third-party software? (I don't see anything related to Boost in

my libraries, at least.)
Well, to be fair, the OP didn't ask for a solution that only used the
standard library. The boost library is a good library that one can download
from boost.org, so I think it deserves to be mentioned.
Also, isn't that a typo? I think you meant to use the << operators before
DID and DPay, right?

No, boost::format overloads the % operator. See
http://www.boost.org/libs/format/doc/format.html

--
David Hilsee