Default parameter of a pointer

[Patrick Kowalzick]

Dear all,

Is the default parameter for t in the function foo guaranteed to be NULL in
the case below ?
(MSVC 7.1 and g++ implements it like that)

#include <iostream>

template <typename T>
void foo(const T & t = T())
{
std::cout << t << std::endl;
}

int main()
{
foo<void*>();
return 0;
}

Thanks,
Patrick

[Mike Wahler]

"Patrick Kowalzick" <ko*******@gmx.net> wrote in message
news:3F****************@nntpserver.swip.net...

Dear all,

Is the default parameter for t in the function foo guaranteed to be NULL in the case below ?
Yes, if the passed argument is a pointer type.
(MSVC 7.1 and g++ implements it like that)

#include <iostream>

template <typename T>
void foo(const T & t = T())

-Mike

[Chris Theis]

"Patrick Kowalzick" <ko*******@gmx.net> wrote in message
news:3F****************@nntpserver.swip.net...

Dear all,

Is the default parameter for t in the function foo guaranteed to be NULL in the case below ?

Yes

[SNIP]

Cheers
Chris