Refering to a template name

[Dave]

Hello,

template <class T>
class weak_ptr
{
weak_ptr(weak_ptr const &r);
};

In the code above, a parameter of type weak_ptr is declared. How is this
possible? weak_ptr is not a type, it's a template! How can me use the name
of a template as a data type?

Thanks,
Dave

[Ioannis Vranos]

Dave wrote:

Hello,

template <class T>
class weak_ptr
{
weak_ptr(weak_ptr const &r);
};

In the code above, a parameter of type weak_ptr is declared. How is this
possible? weak_ptr is not a type, it's a template! How can me use the name
of a template as a data type?

For use inside a template definition you can ommit the type used, so the
above could also have been written as:
template <class T>
class weak_ptr
{
weak_ptr<T>(weak_ptr<T> const &r);
};

--
Ioannis Vranos

http://www23.brinkster.com/noicys

[Rob Williscroft]

Dave wrote in news:10*************@news.supernews.com in comp.lang.c++:

template <class T>
class weak_ptr
{
weak_ptr(weak_ptr const &r);
};

In the code above, a parameter of type weak_ptr is declared. How is
this possible? weak_ptr is not a type, it's a template! How can me
use the name of a template as a data type?

In effect within the scope of weak_ptr< T > weak_ptr is an
alias for weak_ptr< T >.

I can't offhand remember the exact (standard text) of how this
is done, but it is.

IOW: That is how C++ is specified, the alternative would be:

template < typename T >
struct X
{
X< T >( X< T > const &x );
};

Which is just more typing, with no (AFAICT) percivable benefit.

Rob.
--
http://www.victim-prime.dsl.pipex.com/