inheritance / overloading

[Maurice Termeer]

suppose i've got the following:

class a {
public:
virtual void f(int a);
};

class b : public a {
public:
void f(int a, int b);
};

Now I expected that if I had an object o of type b and I would call
o.f(1); that the method of class a would be invoked. However, if I try
this, the compiler says 'b::f does not take one parameter' (msvc++ 2005
beta 2).

How can I solve this? I want o.f(1) to call the method of a, and o.f(1,
2) to call the method of b.

Thanks in advance,

Maurice Termeer

[Sharad Kala]

"Maurice Termeer" <m.*********@student.tue.nl> wrote in message
news:ci*********@news.tue.nl...

suppose i've got the following:

class a {
public:
virtual void f(int a);
};

class b : public a {
public:
void f(int a, int b);
};

Now I expected that if I had an object o of type b and I would call
o.f(1); that the method of class a would be invoked. However, if I try
this, the compiler says 'b::f does not take one parameter' (msvc++ 2005
beta 2).

How can I solve this? I want o.f(1) to call the method of a, and o.f(1,
2) to call the method of b.

This is what Comeau online tells me - "warning: function "a::f(int)" is
hidden by "b::f" --virtual function override intended ? Check the FAQ at
http://www.parashift.com for more details on this. To make a::f visible in b
write this -
class b : public a {
public:
using a::f;
^^^^^^^
....
};

Sharad

[Maurice Termeer]

Sharad Kala wrote:

This is what Comeau online tells me - "warning: function "a::f(int)" is
hidden by "b::f" --virtual function override intended ? Check the FAQ at
http://www.parashift.com for more details on this. To make a::f visible in b
write this -
class b : public a {
public:
using a::f;
^^^^^^^
...
};

thanks! i've never used the using keyword in this context before.. and
that really is a nice reference. too bad i can't download it for offline
viewing anymore.

and quite nice that the problem was listed under "what your mother never
told you" and the whole "it means you're going to die" thing.

Maurice