Hi all.
I have the following code and the 1000 numbers has stored before calling
fifo(),in fifo,why it does not sleep for 1 sec ?it just stop there,but
if i delete sleep(1) ,the number will successfully printed on screen.
Thanks a lot guys!
================================================== ========
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int n[1000];//copy of 1000 numbers
//============================================
//fcfs,fifo:first in first out
void fifo(void){
int reqinter[1000];
for (int i=0;i<1000;i++){
printf("%d ",n[i]);
sleep(1);
}
}
//sst:shortest seek time
void sst(void){
}
//elev:elevator
void elev(void){
}
//cscan:circular scan
void cscan(void){
}
//============================================
//============================================
int main (int argc,char* argv[]) {
//=========get input=================
for(int i=0;i<1000;i++){
scanf("%d",&n[i]);
}
//==========begin to request==========
fifo();
sst();
elev();
cscan();
//====================================
return 0;
}
================================================== ============== 2 5168
"JosephWu" <wu*******@hotmail.com> wrote in message
news:Xn***********************@202.180.64.19... Hi all.
I have the following code and the 1000 numbers has stored before calling fifo(),in fifo,why it does not sleep for 1 sec ?it just stop there,but if i delete sleep(1) ,the number will successfully printed on screen.
You probably need to flush the standard output to make sure that the output
occurs immediately. See below.
Thanks a lot guys!
================================================== ========
#include <stdio.h> #include <stdlib.h> #include <unistd.h>
int n[1000];//copy of 1000 numbers //============================================
//fcfs,fifo:first in first out void fifo(void){ int reqinter[1000]; for (int i=0;i<1000;i++){ printf("%d ",n[i]);
Add this
fflush(stdout);
sleep(1); } }
john
Hi,
"JosephWu" <wu*******@hotmail.com> wrote in message
news:Xn***********************@202.180.64.19... Hi all.
I have the following code and the 1000 numbers has stored before calling fifo(),in fifo,why it does not sleep for 1 sec ?it just stop there,but if i delete sleep(1) ,the number will successfully printed on screen.
Thanks a lot guys!
================================================== ========
#include <stdio.h> #include <stdlib.h> #include <unistd.h>
int n[1000];//copy of 1000 numbers //============================================
//fcfs,fifo:first in first out void fifo(void){ int reqinter[1000]; for (int i=0;i<1000;i++){ printf("%d ",n[i]); sleep(1); } }
Check the return value of sleep
while( sleep(1) );
Though I am not sure what happens with a one second sleep.
sleep can be interrupted on most unix systems by an interrupt and will then
return even if the time hasn't expired!
It will return the seconds that is has to go
Regards, Ron AF Greve. //sst:shortest seek time void sst(void){
}
//elev:elevator void elev(void){
}
//cscan:circular scan void cscan(void){
}
//============================================
//============================================ int main (int argc,char* argv[]) { //=========get input================= for(int i=0;i<1000;i++){ scanf("%d",&n[i]);
}
//==========begin to request==========
fifo(); sst(); elev(); cscan();
//==================================== return 0; }
================================================== ============== This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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