compiling with VC++

[T-Money]

I am trying to build an executable out of source code that supposedly
compiles and is complete but i keep getting errors like the following:

error C2664: cannot convert parameter 2 from
'std::vector<_Ty>::iterator' to 'void *'
with
[
_Ty=pseudoplot
]
Looks to me like something is wrong with the code, but there shouldn't
be. Does anyone know if there is a way to fix this in the compiler
setting/environment.

Thanks,
T

[Victor Bazarov]

T-Money wrote:

I am trying to build an executable out of source code that supposedly
compiles and is complete but i keep getting errors like the following:

error C2664: cannot convert parameter 2 from
'std::vector<_Ty>::iterator' to 'void *'
with
[
_Ty=pseudoplot
]
Looks to me like something is wrong with the code, but there shouldn't
be. Does anyone know if there is a way to fix this in the compiler
setting/environment.

Not in this newsgroup. Try microsoft.public.vc.ide_general or any
other suitable microsoft.public.vc.* newsgroup.

If it's actually a problem with the code, we could try helping you,
but you need to follow the recommendations in the FAQ 5.8.

Victor

[Ali Cehreli]

On Tue, 17 Aug 2004 12:01:22 -0700, T-Money wrote:

I am trying to build an executable out of source code that supposedly
compiles and is complete but i keep getting errors like the following:

error C2664: cannot convert parameter 2 from
'std::vector<_Ty>::iterator' to 'void *'
with
[
_Ty=pseudoplot
]
Looks to me like something is wrong with the code, but there shouldn't
be.
That code must be written under the assumption that vector::iterator is a
typedef of T* (or convertible to T*). The implementation you are using
probably defines vector::iterator as a class.

For example this works with g++ 2.95:

#include <vector>
#include <iostream>

using namespace std;

void foo(int * i)
{
cout << *i << '\n';
}

int main()
{
vector<int> v;
v.push_back(42);
foo(v.begin());
}
Does anyone know if there is a way to fix this in the compiler
setting/environment.

You can rename functions like foo and call them through new functions:

// Renamed
void foo_impl(int * i)
{
cout << *i << '\n';
}

// Uses the address of the object
void foo(vector<int>::iterator iter)
{
return foo_impl(&(*iter));
}

Ali