deleting multible inherited objects using a base class pointer

[Softari]

Why does program crash if object is deleted using base class pointer
that is not the first base class?

Please look exaple below.
#include <iostream>
class A
{
public:
virtual void printA(){std::cout << "A"<<std::endl;}
};

class B
{
public:
virtual void printB(){std::cout << "B"<<std::endl;}
};

class AB:public A, public B
{
};

void foo(A *p){delete p;}
void bar(B *p){delete p;}
int main()
{
AB *p = new AB();
foo(p);
AB *p2 = new AB();
bar(p2); // Crash
return 0;
}

Is there a way around this. I find it quite limiting that the order of
inheritance matters to ability to call foo but not bar
Best Regards,
Jussi

[John Harrison]

On 14 Jul 2004 12:54:02 -0700, Softari <ju********@yahoo.com> wrote:

Why does program crash if object is deleted using base class pointer
that is not the first base class?

Please look exaple below.
#include <iostream>
class A
{
public:
virtual void printA(){std::cout << "A"<<std::endl;}
};

class B
{
public:
virtual void printB(){std::cout << "B"<<std::endl;}
};

class AB:public A, public B
{
};

void foo(A *p){delete p;}
void bar(B *p){delete p;}
int main()
{
AB *p = new AB();
foo(p);
AB *p2 = new AB();
bar(p2); // Crash
return 0;
}

Is there a way around this. I find it quite limiting that the order of
inheritance matters to ability to call foo but not bar
Best Regards,
Jussi

Because you don't have a virtual destructor. It is illegal to delete any
derived object though a base class pointer unless you have a virtual
destructor. First base class, second base class makes no difference, it's
illegal always.
class A
{
public:
virtual ~A() {}
virtual void printA(){std::cout << "A"<<std::endl;}
};

class B
{
public:
virtual ~B() {}
virtual void printB(){std::cout << "B"<<std::endl;}
};

Now it should work.

john