preprocessor, token concatenation, no valid preprocessor token

[Cronus]

Hi

the following code the g++ (g++ (GCC) 3.3.3 (Debian 20040422)) emits the
error message that pasting of :: and hello is no valid preprocessor token.
The g++ 2.95.3 accepts the code. I know that handling of the ##
preprocessing operator has changed.

How I have to change the macro definiton of A(P)?
NO changes at macro calling should be necessary!

Thanks in advance!

#define A(P)****int*P##hello(void)*{return*1;}

class B {
public:
********B()*{
****************b*=*1;
********}

********private:
************************int*b;
************************int*hello();
};

A(D40);
A(B::);

int main(void)**{
}

[Paul Mensonides]

Cronus wrote:

Hi

the following code the g++ (g++ (GCC) 3.3.3 (Debian 20040422)) emits
the error message that pasting of :: and hello is no valid
preprocessor token. The g++ 2.95.3 accepts the code. I know that
handling of the ## preprocessing operator has changed.

How I have to change the macro definiton of A(P)?
NO changes at macro calling should be necessary!

In general, it is not possible to do this. Pasting '::' to 'hello' is undefined
behavior, and you can't make an identifier out of two other identifiers without
token-pasting. Instead, you should get rid of the concatenation and pass the
entire name:

#define A(id) int id(void) {return 1;}

A(D40hello)
A(B::hello)

Further, it is extremely likely that there is a better way to do whatever it is
you're doing (such as tag dispatch + ADL).

Regards,
Paul Mensonides