streaming to a raw buffer

[David Rubin]

How can I stream data to a raw char buffer without using strstream
(which is deprecated), sprintf(), or any copy operation? Here is my
function:

const char *i2bs(unsigned int i, char *buf, int length)
{
// Generate a bit string representation of 'i'. Store the result
in
// 'buf' and return 'buf'. The behavior is undefined if 'buf' is
// null, or 'length' is not large enough to store the result.

static const char *tab[] = // byte to bit conversion table
{
"0000", "0001", "0010", "0011",
"0100", "0101", "0110", "0111",
"1000", "1001", "1010", "1011",
"1100", "1101", "1110", "1111",
};

/*
std::streambuf sbuf; // cannot create basic_streambuf!
sbuf.pubsetbuf(buf, length);

std::ostream os(sbuf);
os << tab[(i >>28) & 0xf] << tab[(i >>24) & 0xf]
<< tab[(i >>20) & 0xf] << tab[(i >>16) & 0xf]
<< tab[(i >>12) & 0xf] << tab[(i >> 8) & 0xf]
<< tab[(i >> 4) & 0xf] << tab[(i >> 0) & 0xf];
*/
return buf;
}

/david

[Siemel Naran]

"David Rubin" <da********@warpmail.net> wrote in message

How can I stream data to a raw char buffer without using strstream
(which is deprecated), sprintf(), or any copy operation? Here is my
function:
The constructor of streambuf is protected, so you can't create one directly.
Conceptually the class is abstract, and that's why you can't create it.
Create a filebuf or stringbuf.

const char *i2bs(unsigned int i, char *buf, int length)
{
// Generate a bit string representation of 'i'. Store the result
in
// 'buf' and return 'buf'. The behavior is undefined if 'buf' is
// null, or 'length' is not large enough to store the result.

static const char *tab[] = // byte to bit conversion table
{
"0000", "0001", "0010", "0011",
"0100", "0101", "0110", "0111",
"1000", "1001", "1010", "1011",
"1100", "1101", "1110", "1111",
};

/*
std::streambuf sbuf; // cannot create basic_streambuf!
sbuf.pubsetbuf(buf, length);

std::ostream os(sbuf);
os << tab[(i >>28) & 0xf] << tab[(i >>24) & 0xf]
<< tab[(i >>20) & 0xf] << tab[(i >>16) & 0xf]
<< tab[(i >>12) & 0xf] << tab[(i >> 8) & 0xf]
<< tab[(i >> 4) & 0xf] << tab[(i >> 0) & 0xf];
*/
return buf;
}

[tom_usenet]

On 18 Jun 2004 09:03:13 -0700, da********@warpmail.net (David Rubin)
wrote:

How can I stream data to a raw char buffer without using strstream
(which is deprecated), sprintf(), or any copy operation?

Write a simpler version of strstreambuf:

class membuf: public std::streambuf
{
public:
membuf(char* mem, std::size_t length)
{
setg(mem, mem, mem + length);
setp(mem, mem + length);
}
};

Tom
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[tom_usenet]

On Fri, 18 Jun 2004 17:36:04 +0100, tom_usenet
<to********@hotmail.com> wrote:

On 18 Jun 2004 09:03:13 -0700, da********@warpmail.net (David Rubin)
wrote:

How can I stream data to a raw char buffer without using strstream
(which is deprecated), sprintf(), or any copy operation?

Write a simpler version of strstreambuf:

class membuf: public std::streambuf
{
public:
membuf(char* mem, std::size_t length)
{
setg(mem, mem, mem + length);
setp(mem, mem + length);
}

It's probably worth overloading the constructor too:

membuf(char const* mem, std::size_t length)
{
setg(mem, mem, mem + length);
}

Tom
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[David Harmon]

On 18 Jun 2004 09:03:13 -0700 in comp.lang.c++, da********@warpmail.net
(David Rubin) wrote,

How can I stream data to a raw char buffer without using strstream
(which is deprecated), sprintf(), or any copy operation?
Feel free to use strstream if it suits your requirements. It's not
going to disappear today.
os << tab[(i >>28) & 0xf] << tab[(i >>24) & 0xf]
<< tab[(i >>20) & 0xf] << tab[(i >>16) & 0xf]
<< tab[(i >>12) & 0xf] << tab[(i >> 8) & 0xf]
<< tab[(i >> 4) & 0xf] << tab[(i >> 0) & 0xf];

os << std::bitset<32>(i);