Dump Memory Pointer?

[Chris Cranford]

Is there anyway that when a function is passed a memory pointer that the
contents of that pointer can be dereferenced or the bytes dumped to a
file or console?

The problem is i have no idea what the pointer really is to and nor do I
have any idea what the total size of the pointer is. I'm trying to
debug something for a friend and this has me stumped and I don't know if
it's even possible.

TIA,
cc

[David Harmon]

On Wed, 14 Apr 2004 15:03:59 -0400 in comp.lang.c++,
ch************@tkdsoftware.com (Chris Cranford) wrote,

Is there anyway that when a function is passed a memory pointer that the
contents of that pointer can be dereferenced or the bytes dumped to a
file or console?

The problem is i have no idea what the pointer really is to and nor do I
have any idea what the total size of the pointer is. I'm trying to
debug something for a friend and this has me stumped and I don't know if
it's even possible.

I suppose you have to guess as to the size of memory area you want to
look at.

Cast the pointer to (unsigned char *). Then hit it with something like
an adaptation of
http://groups.google.com/gr*********....earthlink.net

[Ioannis Vranos]

"Chris Cranford" <ch************@tkdsoftware.com> wrote in message
news:10**************@distinctinnovations.com...

Is there anyway that when a function is passed a memory pointer that the
contents of that pointer can be dereferenced or the bytes dumped to a
file or console?

The problem is i have no idea what the pointer really is to and nor do I
have any idea what the total size of the pointer is. I'm trying to
debug something for a friend and this has me stumped and I don't know if
it's even possible.

Every object in C++ can be considered as an array of unsigned chars which
you can safely *read*. But you have to know the size. Example:
#include <iostream>
#include <vector>
int main()
{
using namespace std;

vector<int>something(10);

unsigned char *p=reinterpret_cast<unsigned char *>(&something);
// std::cout<<static_cast<unsigned>(something[i]); if you want to see
numbers
for(unsigned i=0; i<sizeof(something); ++i)
cout<<p[i];

cout<<endl;

}
All bytes including those with padding bits are printed.


Ioannis Vranos

[Ioannis Vranos]

"Ioannis Vranos" <iv*@guesswh.at.emails.ru> wrote in message
news:c5***********@ulysses.noc.ntua.gr...

// std::cout<<static_cast<unsigned>(something[i]); if you want to see
numbers

// std::cout<<static_cast<unsigned>(p[i]); if you want to see numbers


Ioannis Vranos

[Christopher Benson-Manica]

Chris Cranford <ch************@tkdsoftware.com> spoke thus:

The problem is i have no idea what the pointer really is to and nor do I
have any idea what the total size of the pointer is. I'm trying to
debug something for a friend and this has me stumped and I don't know if
it's even possible.

How can you have no idea what the pointer is? If it isn't a pointer
to a type you know about, then it's a void pointer. If it's a void
pointer, you 1) can't dereference it directly, and 2) can't
dereference it at all unless you figure out (preferably by reading the
code, although I guess you could static_cast randomly...) what it was
pointing to. And you can't "dump" what a pointer is pointing to
without dereferencing the pointer.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[Christopher Benson-Manica]

Christopher Benson-Manica <at***@nospam.cyberspace.org> spoke thus:

...
pointing to. And you can't "dump" what a pointer is pointing to
without dereferencing the pointer.

^
Or, of course, by knowing the size of what it's pointing to.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.