Hi!
I have the following scenario:
class QWidget
{}
class GeneratedClass : public QWidget
{}
class AbstractPanel
{
virtual void AbsMethod() = 0;
}
class MyClass : public GeneratedClass , AbstractPanel
{
void AbsMethod() {;} // impl
}
I have the QWidget pointer, how can I cast it so that I can
make a call to the AbsMethod implemented by MyClass ?
thanx a lot ...
bye
--
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AriZOnA wrote: Hi! I have the following scenario:
class QWidget {}
class GeneratedClass : public QWidget {}
class AbstractPanel { virtual void AbsMethod() = 0; }
class MyClass : public GeneratedClass , AbstractPanel
Was the private inheritance from AbstractPanel intentional?
{ void AbsMethod() {;} // impl }
I have the QWidget pointer, how can I cast it so that I can make a call to the AbsMethod implemented by MyClass ?
I assume QWidget is polymorphic (Well, I know Qt :-) ) and the
inheritance from AbstractPanel was supposed to be public.
Use dynamic_cast:
if (MyClass* p = dynamic_cast<MyClass*>(thewidgetpointer))
p->AbsMethod();
else
std::cerr << "your QWidget isn't an instance of MyClass\n";
"AriZOnA" <wa*@libero.it> wrote: Hi! I have the following scenario:
class QWidget {}
class GeneratedClass : public QWidget {}
class AbstractPanel { virtual void AbsMethod() = 0; }
class MyClass : public GeneratedClass , AbstractPanel { void AbsMethod() {;} // impl }
I have the QWidget pointer, how can I cast it so that I can make a call to the AbsMethod implemented by MyClass ?
How do you know that the object in the QWidget pointer you have
implements the AbsMethod?
On Wed, 14 Apr 2004 11:25:14 +0000 (UTC), "AriZOnA" <wa*@libero.it>
wrote: Hi! I have the following scenario:
class QWidget {}
class GeneratedClass : public QWidget {}
class AbstractPanel { virtual void AbsMethod() = 0; }
class MyClass : public GeneratedClass , AbstractPanel { void AbsMethod() {;} // impl }
I have the QWidget pointer, how can I cast it so that I can make a call to the AbsMethod implemented by MyClass ?
Assuming QWidget has at least 1 virtual function (and surely it has a
virtual destructor), you can do:
if (MyClass* p = dynamic_cast<MyClass*>(qptr))
{
p->AbsMethod();
}
(or dynamic_cast to AbstractPanel instead).
Tom
--
C++ FAQ: http://www.parashift.com/c++-faq-lite/
C FAQ: http://www.eskimo.com/~scs/C-faq/top.html
tom_usenet <to********@hotmail.com> wrote: "AriZOnA" <wa*@libero.it> wrote:
class QWidget {}
class GeneratedClass : public QWidget {}
class AbstractPanel { virtual void AbsMethod() = 0; }
class MyClass : public GeneratedClass , AbstractPanel { void AbsMethod() {;} // impl }
I have the QWidget pointer, how can I cast it so that I can make a call to the AbsMethod implemented by MyClass ? Assuming QWidget has at least 1 virtual function (and surely it has a virtual destructor), you can do:
if (MyClass* p = dynamic_cast<MyClass*>(qptr)) { p->AbsMethod(); }
If you expect qptr to always be a MyClass *, you can go:
dynamic_cast<MyClass &>(*qptr).AbsMethod();
which will throw a std::bad_cast exception if qptr was not a
MyClass *.
(or dynamic_cast to AbstractPanel instead).
Is it safe to "sideways" dynamic cast? I've only ever used it
where the cast-to class was a direct descendent of the cast-from class. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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