I am posting the gcc 3.3.2 compiler error and the source lines below
them. Please explain this warning and how to fix it.
crt/crtmap.hpp:17: warning: `std::map<K, D, C,
std::allocator<std::pair<const
_Key, _Tp> > >::iterator' is implicitly a typename
crt/crtmap.hpp:17: warning: implicit typename is deprecated, please see the
documentation for details
crt/crtmap.hpp:18: warning: `std::map<K, D, C,
std::allocator<std::pair<const
_Key, _Tp> > >::const_iterator' is implicitly a typename
crt/crtmap.hpp:18: warning: implicit typename is deprecated, please see the
documentation for details
----------------
Here is the offending code:
template <class K,class D,class C>
class CRTMap
{
private:
mutable std::map<K,D,C> mymap;
mutable CRTMLock MLock;
public:
typedef std::map<K,D,C>::iterator iterator; //// Line 17
typedef std::map<K,D,C>::const_iterator const_iterator; //// Line 18
inline CRTMap(void)
{
}
[...]
4  2022 
On Sat, 03 Apr 2004 22:24:08 -0500, DFP <DF*@nospam.net> wrote: I am posting the gcc 3.3.2 compiler error and the source lines below
them. Please explain this warning and how to fix it.
Isn't this in the FAQ yet? :-)
crt/crtmap.hpp:17: warning: `std::map<K, D, C,
std::allocator<std::pair<const
_Key, _Tp> > >::iterator' is implicitly a typename
crt/crtmap.hpp:17: warning: implicit typename is deprecated, please see the
documentation for details
crt/crtmap.hpp:18: warning: `std::map<K, D, C,
std::allocator<std::pair<const
_Key, _Tp> > >::const_iterator' is implicitly a typename
crt/crtmap.hpp:18: warning: implicit typename is deprecated, please see the
documentation for details
----------------
Here is the offending code:
template <class K,class D,class C>
class CRTMap
{
private:
mutable std::map<K,D,C> mymap;
mutable CRTMLock MLock;
public:
typedef std::map<K,D,C>::iterator iterator; //// Line 17
typedef typename std::map<K,D,C>::iterator iterator;
typedef std::map<K,D,C>::const_iterator const_iterator; //// Line 18
typedef typename std::map<K,D,C>::const_iterator const_iterator;
ISO C++ requires type names (as opposed to other kinds of names) dependent
upon a template parameter to be qualified with the keyword "typename". Some
compilers make do without the 'typename', although the code is not
compliant without it.
-leor
--
Leor Zolman --- BD Software --- www.bdsoft.com
On-Site Training in C/C++, Java, Perl and Unix
C++ users: Download BD Software's free STL Error Message Decryptor at: www.bdsoft.com/tools/stlfilt.html
On Sat, 03 Apr 2004 22:24:08 -0500, DFP <DF*@nospam.net> wrote: I am posting the gcc 3.3.2 compiler error and the source lines below
them. Please explain this warning and how to fix it.
Isn't this in the FAQ yet? :-)
crt/crtmap.hpp:17: warning: `std::map<K, D, C,
std::allocator<std::pair<const
_Key, _Tp> > >::iterator' is implicitly a typename
crt/crtmap.hpp:17: warning: implicit typename is deprecated, please see the
documentation for details
crt/crtmap.hpp:18: warning: `std::map<K, D, C,
std::allocator<std::pair<const
_Key, _Tp> > >::const_iterator' is implicitly a typename
crt/crtmap.hpp:18: warning: implicit typename is deprecated, please see the
documentation for details
----------------
Here is the offending code:
template <class K,class D,class C>
class CRTMap
{
private:
mutable std::map<K,D,C> mymap;
mutable CRTMLock MLock;
public:
typedef std::map<K,D,C>::iterator iterator; //// Line 17
typedef typename std::map<K,D,C>::iterator iterator;
typedef std::map<K,D,C>::const_iterator const_iterator; //// Line 18
typedef typename std::map<K,D,C>::const_iterator const_iterator;
ISO C++ requires type names (as opposed to other kinds of names) dependent
upon a template parameter to be qualified with the keyword "typename". Some
compilers make do without the 'typename', although the code is not
compliant without it.
-leor
--
Leor Zolman --- BD Software --- www.bdsoft.com
On-Site Training in C/C++, Java, Perl and Unix
C++ users: Download BD Software's free STL Error Message Decryptor at: www.bdsoft.com/tools/stlfilt.html
DFP wrote: typedef std::map<K,D,C>::iterator iterator; //// Line 17
typedef std::map<K,D,C>::const_iterator const_iterator; //// Line 18
"//" is sufficient to mark a comment in C++.
typedef typename std::map<K,D,C>::iterator iterator;
typedef typename std::map<K,D,C>::const_iterator const_iterator;
The rule is that std::map<K,D,C>::iterator is assumed to be the name of
an object unless you say that it's the name of a type.
--
Pete Becker
Dinkumware, Ltd. ( http://www.dinkumware.com)
DFP wrote: typedef std::map<K,D,C>::iterator iterator; //// Line 17
typedef std::map<K,D,C>::const_iterator const_iterator; //// Line 18
"//" is sufficient to mark a comment in C++.
typedef typename std::map<K,D,C>::iterator iterator;
typedef typename std::map<K,D,C>::const_iterator const_iterator;
The rule is that std::map<K,D,C>::iterator is assumed to be the name of
an object unless you say that it's the name of a type.
--
Pete Becker
Dinkumware, Ltd. ( http://www.dinkumware.com) This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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