please help me...

[Pat]

Hi,
I want to use "new" to build an array test[1000][1000]. Can you tell me how
to do?

Thank.

Pat

[Pat]

I don't want to use "int test[1000][1000]".

Thanks.
"Pat" <Pa*@Pat.com> ¦b¶l¥ó news:40**********@rain.i-cable.com ¤¤¼¶¼g...

Hi,
I want to use "new" to build an array test[1000][1000]. Can you tell me how to do?

Thank.

Pat

[AirPete]

Pat wrote:

I don't want to use "int test[1000][1000]".

Thanks.
"Pat" <Pa*@Pat.com> ¦b¶l¥ó news:40**********@rain.i-cable.com
¤¤¼¶¼g...

Hi,
I want to use "new" to build an array test[1000][1000]. Can you tell
me how to do?

Thank.

Pat

Try a jagged vector of vectors:

(not compiled)

vector<vector<int> > arr;
arr.resize(1000);
for(int i =0;i<1000;++i)
arr[i].resize(1000);

Then simply:
arr[x][y] = 1234;

- Pete

[osmium]

Pat writes:

I want to use "new" to build an array test[1000][1000]. Can you tell me how to do?

This works.

<add boilerplate>

void foo(int b[][4])
{
cout << b[2][3] << endl;
}

void test()
{
int(*a)[4] = new int[3][4];
a[2][3] = 1024;
foo(a);
}

[Mike Wahler]

"Pat" <Pa*@Pat.com> wrote in message news:40**********@rain.i-cable.com...

Hi,
I want to use "new" to build an array test[1000][1000]. Can you tell me how to do?

http://www.parashift.com/c++-faq-lit...html#faq-16.15

Always check the FAQ before posting a question.

-Mike

[TJB]

"Pat" <Pa*@Pat.com> wrote in message news:40**********@rain.i-cable.com...

Hi,
I want to use "new" to build an array test[1000][1000]. Can you tell me how to do?

Thank.

Pat

Hi,

You have to create an array of arrays like this:

int i,**test;

test = new int*[1000];
for (i = 0; i < 1000; i++)
test[i] = new int[1000];

You could also start with an array of pointers, int* test[1000], and
initialize the elements in it.

[Alf P. Steinbach]

* "TJB" <ce*******@telia.com> schriebt:

"Pat" <Pa*@Pat.com> wrote in message news:40**********@rain.i-cable.com...

I want to use "new" to build an array test[1000][1000]. Can you tell me
how to do?

You have to create an array of arrays like this:

int i,**test;

test = new int*[1000];
for (i = 0; i < 1000; i++)
test[i] = new int[1000];

You could also start with an array of pointers, int* test[1000], and
initialize the elements in it.

Well no, e doesn't "have to".

Except if e _really_ doesn't want a two-dimensional array.

See the answer from osmium earlier in the thread about how to allocate
a two-dimensional array using new,

int (*p)[1000] = new int[1000][1000];

The general question is also a FAQ, see
<url: http://www.parashift.com/c++-faq-lite/freestore-mgmt.html#faq-16.15>,
"How do I allocate a multidimensional array using new?"

Unfortunately, in spite of the heading the FAQ does not show how to allocate
a multidimensional array using new (!), only jagged arrays like yours. But
it does go on to show a few generally much better ways.

--
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?

[LNK2005]

"osmium" <r1********@comcast.net> skrev i meddelandet
news:c2*************@ID-179017.news.uni-berlin.de...

Pat writes:
int(*a)[4] = new int[3][4];

Maybe you should point out that this only works if the number of items in
the second dimension (=4) is known at compile time, which limits the
usefullness of this method.