Problem with convoluted function pointer

[Christopher Benson-Manica]

Given

typedef bool (TMyType::* FTYPE)(const void*,unsigned int, unsigned
int, unsigned int);

class TMyType{
public:
bool Send( const void *, unsigned int, unsigned int, unsigned int );
};

class TMyDerivedType : public TMyType
{
private:
A a;

public:
TMyDerivedType() : a(&TMyType::Send) {}
};
class A
{
private:
FTYPE f;

public:
void do_stuff() {f(NULL,1,2,3);}
A( FTYPE func ) {f=func;}
};

Why is f(NULL...) "call of nonfunction?" What have I done wrong?

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[John Harrison]

"Christopher Benson-Manica" <at***@nospam.cyberspace.org> wrote in message
news:c1**********@chessie.cirr.com...

Given

typedef bool (TMyType::* FTYPE)(const void*,unsigned int, unsigned
int, unsigned int);

class TMyType{
public:
bool Send( const void *, unsigned int, unsigned int, unsigned int );
};

class TMyDerivedType : public TMyType
{
private:
A a;

public:
TMyDerivedType() : a(&TMyType::Send) {}
};
class A
{
private:
FTYPE f;

public:
void do_stuff() {f(NULL,1,2,3);}
A( FTYPE func ) {f=func;}
};

Why is f(NULL...) "call of nonfunction?" What have I done wrong?

Not followed the correct syntax for pointers to member functions

From memory,

(this->*f)(NULL,1,2,3);

john

[Rob Williscroft]

Christopher Benson-Manica wrote in news:c1**********@chessie.cirr.com:

Given

typedef bool (TMyType::* FTYPE)(const void*,unsigned int, unsigned
int, unsigned int);

class TMyType{
public:
bool Send( const void *, unsigned int, unsigned int, unsigned int );
};

class TMyDerivedType : public TMyType
{
private:
A a;

public:
TMyDerivedType() : a(&TMyType::Send) {}
};
class A
{
private:
FTYPE f;

public:
void do_stuff() {f(NULL,1,2,3);}
A( FTYPE func ) {f=func;}
};

Why is f(NULL...) "call of nonfunction?" What have I done wrong?

Member pointers only contain a reference to the member not the object,
to call via such a pointer you need an object:

FTYPE f = &TMyType::send;

TMyType obj, *ptr = &obj;

(obj.*f)( NULL, 1, 2, 3 );
(ptr->*f)( NULL, 1, 2, 3 );

HTH.

Rob.
--
http://www.victim-prime.dsl.pipex.com/

[Christopher Benson-Manica]

John Harrison <jo*************@hotmail.com> spoke thus:

typedef bool (TMyType::* FTYPE)(const void*,unsigned int, unsigned
int, unsigned int);

class TMyType{
public:
bool Send( const void *, unsigned int, unsigned int, unsigned int );
};

class TMyDerivedType : public TMyType
{
private:
A a;

public:
TMyDerivedType() : a(&TMyType::Send) {}
};

class A
{
private:
FTYPE f;

public:
void do_stuff() {f(NULL,1,2,3);}
A( FTYPE func ) {f=func;}
};

(left for context)
(this->*f)(NULL,1,2,3);

Okay, thanks - that works. Unfortunately, now I'm informed that
TMyType is not a public base class of A... Now what? I should
probably note here that TMyDerivedType has it's own Send() function,
with a different signature.

(Thanks so much for continuing to bear with me!)

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[Christopher Benson-Manica]

Christopher Benson-Manica <at***@nospam.cyberspace.org> spoke thus:

(this->*f)(NULL,1,2,3);

Okay, thanks - that works. Unfortunately, now I'm informed that
TMyType is not a public base class of A... Now what? I should
probably note here that TMyDerivedType has it's own Send() function,
with a different signature.

Ah, I see what I wanted - not MyType::Send, but this->MyType::Send,
changing the typedef accordingly of course. At least it compiles
now...

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.