Pass pointer by reference

[Nelson]

Hi,

Can pointers be passed by reference to functions? If so, how to do it?

Or is there any other way to change the pointers in the caller by the
called function?

Thanks,
Nelson

[Jakob Bieling]

"Nelson" <do*******@hotmail.com> wrote in message
news:6a**************************@posting.google.c om...

Hi,

Can pointers be passed by reference to functions? If so, how to do it?
Yes, like this:

void test_func (int*& i);

'i' as a reference to a pointer to an int.
Or is there any other way to change the pointers in the caller by the
called function?

Yes, you can also pass the pointers address. In that case your function
would look like this:

void test_func (int** i);

hth
--
jb

(replace y with x if you want to reply by e-mail)

[Rolf Magnus]

Nelson wrote:

Hi,

Can pointers be passed by reference to functions?
Yes, just like any other type.
If so, how to do it?
Also the same as any other type - by adding an '&' between type and
name.
Or is there any other way to change the pointers in the caller by the
called function?

You could pass a pointer to pointer, or you could return the pointer
from your function, so that the caller can assign the result to a
target variable.