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# access the fields of a struct by position rather than name

 P: n/a Does anyone know how to do this in C++ or if it can be done? And also to find out how many fields there are in a struct? Jul 22 '05 #1
6 Replies

 P: n/a "J" wrote in message news:94*************************@posting.google.co m... Does anyone know how to do this in C++ or if it can be done? It can be done with very crude casting and pointer arithmetic, but its definitely a bad idea. And also to find out how many fields there are in a struct? That cannot be done. Almost certainly you are trying the wrong approach, either you need to change your approach or you need to change your language. Why not explain what you are actually trying to achieve and better advice can be given. john Jul 22 '05 #2

 P: n/a "John Harrison" wrote in message news:c0*************@ID-196037.news.uni-berlin.de... "J" wrote in message news:94*************************@posting.google.co m... Does anyone know how to do this in C++ or if it can be done? It can be done with very crude casting and pointer arithmetic, but its definitely a bad idea. And also to find out how many fields there are in a struct? That cannot be done. Almost certainly you are trying the wrong approach, either you need to change your approach or you need to change your language. Why not explain what you are actually trying to achieve and better advice can be given. john Perhaps something like this, I'm assuming that all your fields are int's struct Base { virtual ~Base() {} virtual int num_fields() = 0; virtual int get_field(int n) = 0; virtual void set_field(int n, int val) = 0; }; struct Pair : public Base // a struct with two fields { virtual int num_fields() { return 2; } virtual int get_field(int n) { if (n == 0) return first; else if (n == 1) return second; else error("not enough fields"); } virtual void set_field(int n, int val) { if (n == 0) first = val; else if (n == 1) second = val; else error("not enough fields"); } int first; int second; }; That's how you'd do it in C++, if you really have to do it at all. john Jul 22 '05 #3

 P: n/a "J" wrote: Does anyone know how to [access the fields of a struct by position rather than name] in C++ or if it can be done? This might not be what you are really asking, but there is a macro offsetof(type, fieldname) in ( ?) This will only be useful to you if you know in advance the types of all the fields, or if they all have the same type. You might be interested in the boost::Any template class, which can be used to create a heterogeneous list of values (ie.different types, just like a struct): http://www.boost.org/doc/html/any.html http://www.boost.org/doc/html/ch02s02.html (example of a list of boost::Any) David F Jul 22 '05 #4

 P: n/a > Perhaps something like this, I'm assuming that all your fields are int's struct Base { virtual ~Base() {} virtual int num_fields() = 0; virtual int get_field(int n) = 0; virtual void set_field(int n, int val) = 0; }; struct Pair : public Base // a struct with two fields { virtual int num_fields() { return 2; } virtual int get_field(int n) { if (n == 0) return first; else if (n == 1) return second; else error("not enough fields"); } virtual void set_field(int n, int val) { if (n == 0) first = val; else if (n == 1) second = val; else error("not enough fields"); } int first; int second; }; That's how you'd do it in C++, if you really have to do it at all. john This is what I am looking for but I was hoping C++ would have the features built in, rather than having to extend the structures. Have you heard of Tuples? Could something similar also be done with Tuples? J Jul 22 '05 #5

 P: n/a "J" wrote in message news:94**************************@posting.google.c om... Perhaps something like this, I'm assuming that all your fields are int's struct Base { virtual ~Base() {} virtual int num_fields() = 0; virtual int get_field(int n) = 0; virtual void set_field(int n, int val) = 0; }; struct Pair : public Base // a struct with two fields { virtual int num_fields() { return 2; } virtual int get_field(int n) { if (n == 0) return first; else if (n == 1) return second; else error("not enough fields"); } virtual void set_field(int n, int val) { if (n == 0) first = val; else if (n == 1) second = val; else error("not enough fields"); } int first; int second; }; That's how you'd do it in C++, if you really have to do it at all. john This is what I am looking for but I was hoping C++ would have the features built in, rather than having to extend the structures. Have you heard of Tuples? Could something similar also be done with Tuples? J There's a very sophisticated Tuple implementation in the Loki library, it allows any arbitary number and type of fields. Everything is worked out at compile time instead of runtime like my crude code. http://sourceforge.net/projects/loki-lib/ Boost also have a tuple library, don't know anything about that however. http://www.boost.org/ john Jul 22 '05 #6

 P: n/a "John Harrison" wrote in message news:c0*************@ID-196037.news.uni-berlin.de... "J" wrote in message news:94**************************@posting.google.c om... There's a very sophisticated Tuple implementation in the Loki library, it allows any arbitary number and type of fields. Everything is worked out at compile time instead of runtime like my crude code. http://sourceforge.net/projects/loki-lib/ Boost also have a tuple library, don't know anything about that however. http://www.boost.org/ Definitely learn the boost version, as it, or an extension, will likely be in the next standard. Jonathan Jul 22 '05 #7

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