How to make Template functions friends to a class

[madhukar_bm]

Can we declare a template function as a friend to a class, if yes
please give me the syntax.Thanks in advance
rgrds
Madhukar

[David Harmon]

On 5 Feb 2004 02:46:27 -0800 in comp.lang.c++, ma********@yahoo.com
(madhukar_bm) was alleged to have written:

Can we declare a template function as a friend to a class, if yes

This issue is covered in Marshall Cline's C++ FAQ. See the topic
"[34.15] Why do I get linker errors when I use template friends?" It
is always good to check the FAQ before posting. You can get the FAQ at:
http://www.parashift.com/c++-faq-lite/

[Gianni Mariani]

madhukar_bm wrote:

Can we declare a template function as a friend to a class, if yes
please give me the syntax.Thanks in advance
rgrds
Madhukar

Yes.

class foo
{
public:
template <typename x> friend class x;
int y;
};
template <typename x> class x
{
public:
void func( foo * x )
{
x->y =2;
}
};
I didn't compiler the code above but it *should* work.