implementing a templated struct within a templated struct

[RA Scheltema]

hi all,
Basically I have the following situation in my header-file:

---
....

template <typename ta_type>
struct A
{
template<size_t ta_size>
struct B
{
inline void do_something_big();
};
};

#include "A.inl"

....
---
The function do_something_big contains quite a lot of code and for obvious
keeping it clean reasons I want to implement this function in the .inl file.

My question is, how would I do this. First of all I'm thinking I will get
stuck with the

A::B::do_something_big

definition, but next to this I have two template definitions to make before
I can even start with typing this !

Is this at all possible ?

kind regards,
richard

[Gerrit Gruben]

template <typename T>

template <size_t size>

void A<T>::B<size>::do_something_big()

[Jeff Schwab]

RA Scheltema wrote:

hi all,
Basically I have the following situation in my header-file:

---
...

template <typename ta_type>
struct A
{
template<size_t ta_size>
struct B
{
inline void do_something_big();
};
};

#include "A.inl"

...
---
The function do_something_big contains quite a lot of code and for obvious
keeping it clean reasons I want to implement this function in the .inl file.

My question is, how would I do this. First of all I'm thinking I will get
stuck with the

A::B::do_something_big

definition, but next to this I have two template definitions to make before
I can even start with typing this !

Is this at all possible ?

kind regards,
richard

If you know it's "big," why are you declaring it inline?

Anyway, it's worse than A::B::do_something_big( ). Try this:

template< typename ta_type >
template< size_t ta_size >
void A<ta_type>::B<ta_size>::do_something_big( )
{
// ...
}

[RA Scheltema]

hi there,

been reading some visual c++ docs (the compiler of my choice :( ...) and
just found out that this construction isn't possible there. stupid of me to
expect that visual c++ could do something useful :). anyway, the largeness
of the code is of course relative. I just thought it cleaner to put it in
some outside implementation as not to clutter up my header, but alas
thanks for the reactions
richard
"RA Scheltema" <r.a.scheltema[viral][s][p]@[m]dacolian.nl> schreef in
bericht news:3f*********************@news.xs4all.nl...

hi all,
Basically I have the following situation in my header-file:

---
...

template <typename ta_type>
struct A
{
template<size_t ta_size>
struct B
{
inline void do_something_big();
};
};

#include "A.inl"

...
---
The function do_something_big contains quite a lot of code and for obvious
keeping it clean reasons I want to implement this function in the .inl file.
My question is, how would I do this. First of all I'm thinking I will get
stuck with the

A::B::do_something_big

definition, but next to this I have two template definitions to make before I can even start with typing this !

Is this at all possible ?

kind regards,
richard