By using this site, you agree to our updated Privacy Policy and our Terms of Use. Manage your Cookies Settings.
446,260 Members | 1,305 Online
Bytes IT Community
+ Ask a Question
Need help? Post your question and get tips & solutions from a community of 446,260 IT Pros & Developers. It's quick & easy.

Need to write a function that adjusts words in a string array

P: n/a
I have a program that reads from a file. In the file are a series of
words. I read in all the words into a string array, find the average
length, count the number of words, display the longest word and how long
it is, and display the smallest word and how long it is. All that is
working fine, but what I need to do it format certain words that contain
a period at the end of them (ex: a word at the end of a sentence), words
with quotes around them, exclamation points, etc. If a word has one of
these characters anywhere but the beginning or end it is ok. Also, say
you have this word: one." It needs to be changed to: one

The word: don't is ok because the "'" isn't at the beginning or end.

Jul 22 '05 #1
Share this Question
Share on Google+
8 Replies


P: n/a
On Mon, 24 Nov 2003 15:23:46 -0800, Rick wrote:
I have a program that reads from a file. In the file are a series of
words. I read in all the words into a string array, find the average
length, count the number of words, display the longest word and how long
it is, and display the smallest word and how long it is. All that is
working fine, but what I need to do it format certain words that contain
a period at the end of them (ex: a word at the end of a sentence), words
with quotes around them, exclamation points, etc. If a word has one of
these characters anywhere but the beginning or end it is ok. Also, say
you have this word: one." It needs to be changed to: one

The word: don't is ok because the "'" isn't at the beginning or end.


That task can easily be accomplished with regular expressions. Look at
Regex++ (http://www.boost.org/libs/regex/index.htm), included in Boost.

Regards,
Henk Burgstra
Jul 22 '05 #2

P: n/a
It needs to be done basically with if/for/while loops.

Henk Burgstra wrote:
On Mon, 24 Nov 2003 15:23:46 -0800, Rick wrote:

I have a program that reads from a file. In the file are a series of
words. I read in all the words into a string array, find the average
length, count the number of words, display the longest word and how long
it is, and display the smallest word and how long it is. All that is
working fine, but what I need to do it format certain words that contain
a period at the end of them (ex: a word at the end of a sentence), words
with quotes around them, exclamation points, etc. If a word has one of
these characters anywhere but the beginning or end it is ok. Also, say
you have this word: one." It needs to be changed to: one

The word: don't is ok because the "'" isn't at the beginning or end.

That task can easily be accomplished with regular expressions. Look at
Regex++ (http://www.boost.org/libs/regex/index.htm), included in Boost.

Regards,
Henk Burgstra


Jul 22 '05 #3

P: n/a
How do I check if tempword[0] equals a '

I get an error when I do tempword[0] == '''

How do I format it different?

void convertarray(string words[], int count)
{
//int firstpos;
int lastpos;
string tempword;
int length;

for(int i = 0; i < count; i++)
{
//firstpos = 0;
tempword = words[i];
lastpos = tempword.length() - 1;
if(tempword[0] == '!' || tempword[0] == '(' || ')' || tempword[0]
== '"' || tempword[0] == '?' ||
tempword[0] == '.' || tempword[0] == ':' || tempword[0] == ';' ||
tempword[0] == ''' ||
tempword[0] == ',')
{
length = tempword.length();
for(int j = 0; j < length - 1; j++)
tempword[j] = tempword[j + 1];
}
}
}

Rick wrote:
I have a program that reads from a file. In the file are a series of
words. I read in all the words into a string array, find the average
length, count the number of words, display the longest word and how long
it is, and display the smallest word and how long it is. All that is
working fine, but what I need to do it format certain words that contain
a period at the end of them (ex: a word at the end of a sentence), words
with quotes around them, exclamation points, etc. If a word has one of
these characters anywhere but the beginning or end it is ok. Also, say
you have this word: one." It needs to be changed to: one

The word: don't is ok because the "'" isn't at the beginning or end.


Jul 22 '05 #4

P: n/a
Ok, this is what I have right now. It's not working quite properly and
I still need to check to see if the first character is a: '

For some reason every word is being converted even though some should
make the if statement false.

void convertarray(string words[], int count)
{
//int firstpos;
int lastpos;
string tempword;
int length;
bool yes;

for(int i = 0; i < count; i++)
{
tempword = words[i];
lastpos = tempword.length() - 1;
if(tempword[0] == '!' || tempword[0] == '(' || ')' || tempword[0]
== '"' || tempword[0] == '?' ||
tempword[0] == '.' || tempword[0] == ':' || tempword[0] == ';' ||
tempword[0] == ',')
{
length = tempword.length();
for(int j = 0; j < length - 1; j++)
tempword[j] = tempword[j + 1];
words[i] = tempword;
}
else
{
words[i] = tempword;
}
}
}

Rick wrote:
How do I check if tempword[0] equals a '

I get an error when I do tempword[0] == '''

How do I format it different?

void convertarray(string words[], int count)
{
//int firstpos;
int lastpos;
string tempword;
int length;

for(int i = 0; i < count; i++)
{
//firstpos = 0;
tempword = words[i];
lastpos = tempword.length() - 1;
if(tempword[0] == '!' || tempword[0] == '(' || ')' || tempword[0]
== '"' || tempword[0] == '?' ||
tempword[0] == '.' || tempword[0] == ':' || tempword[0] == ';' ||
tempword[0] == ''' ||
tempword[0] == ',')
{
length = tempword.length();
for(int j = 0; j < length - 1; j++)
tempword[j] = tempword[j + 1];
}
}
}

Rick wrote:
I have a program that reads from a file. In the file are a series of
words. I read in all the words into a string array, find the average
length, count the number of words, display the longest word and how
long it is, and display the smallest word and how long it is. All
that is working fine, but what I need to do it format certain words
that contain a period at the end of them (ex: a word at the end of a
sentence), words with quotes around them, exclamation points, etc. If
a word has one of these characters anywhere but the beginning or end
it is ok. Also, say you have this word: one." It needs to be
changed to: one

The word: don't is ok because the "'" isn't at the beginning or end.


Jul 22 '05 #5

P: n/a
In article <Mnywb.6324$ML6.1502@fed1read01>,
Rick <rf*****@NOSPAMcox.net> wrote:
How do I check if tempword[0] equals a '

I get an error when I do tempword[0] == '''


Try tempword[0] == '\''

The backslash tells the compiler that you want it to use the second ' as a
literal character, not as a quote mark to delimit another character (its
normal function in a C++ statement).

--
Jon Bell <jt*******@presby.edu> Presbyterian College
Dept. of Physics and Computer Science Clinton, South Carolina USA
Jul 22 '05 #6

P: n/a
I got that, but I'm still not getting the desired output. Here is what
I have so far:

void convertarray(string words[], int count)
{
int lastpos;
string tempword;
int length;
bool yes;

for(int i = 0; i < count; i++)
{
tempword = words[i]; //file?
lastpos = tempword.length() - 1; //4
if(tempword[0] == '!' || tempword[0] == '(' || ')' || tempword[0]
== '"' || tempword[0] == '?' ||
tempword[0] == '.' || tempword[0] == ':' || tempword[0] == ';' ||
tempword[0] == ',' ||
tempword[0] == '\'')
{
cout << "first position matches" << endl;
length = tempword.length();
for(int j = 0; j < length + 1; j++)
tempword[j] = tempword[j];
words[i] = tempword;
}
if(tempword[lastpos] == '!' || tempword[lastpos] == '(' ||
tempword[lastpos] == '"' ||
tempword[lastpos] == '?' || tempword[lastpos] == '.' ||
tempword[lastpos] == ';' ||
tempword[lastpos] == ',' || tempword[lastpos] == '\'')
{
cout << "last position matches" << endl;
length = tempword.length(); //4
for(int k = 0; k < length; k++)
tempword[k] = tempword[k];//file
words[i] = tempword;
}
else
{
cout << "no position matches" << endl;
words[i] = tempword;
}
}
}

Jon Bell wrote:
In article <Mnywb.6324$ML6.1502@fed1read01>,
Rick <rf*****@NOSPAMcox.net> wrote:
How do I check if tempword[0] equals a '

I get an error when I do tempword[0] == '''

Try tempword[0] == '\''

The backslash tells the compiler that you want it to use the second ' as a
literal character, not as a quote mark to delimit another character (its
normal function in a C++ statement).


Jul 22 '05 #7

P: n/a


Rick wrote:

I got that, but I'm still not getting the desired output. Here is what
I have so far:
Devloping debug techniques is something you need to learn.
Just in case you don't have a debugger (which would simplify
things) why not insert some output statements at strategic
positions to enable yourself to watch what the program
is doing and why.

eg.

void convertarray(string words[], int count)
{
int lastpos;
string tempword;
int length;
bool yes;

for(int i = 0; i < count; i++)
{
tempword = words[i]; //file?
lastpos = tempword.length() - 1; //4
cout << "word is " << tempword << endl;
cout << "lastpos: " << lastpos << endl;
if(tempword[0] == '!' || tempword[0] == '(' || ')' || tempword[0]
== '"' || tempword[0] == '?' ||
tempword[0] == '.' || tempword[0] == ':' || tempword[0] == ';' ||
tempword[0] == ',' ||
tempword[0] == '\'')
{
cout << "first position matches" << endl;
length = tempword.length();
cout << "copying first" << length << " characters" << endl;
for(int j = 0; j < length + 1; j++) {
cout << "copy " << tempword[j] << " (" << j << ") to position" << j << endl;
tempword[j] = tempword[j]; }
words[i] = tempword;
cout << "new word is " << tempword << endl;

// note: the above loop does .... nothing
// that means, of course it does something. It copies
// the j-th character to the j-th character. In the
// end tempword hasn't changed :-)
}
if(tempword[lastpos] == '!' || tempword[lastpos] == '(' ||
tempword[lastpos] == '"' ||
tempword[lastpos] == '?' || tempword[lastpos] == '.' ||
tempword[lastpos] == ';' ||
tempword[lastpos] == ',' || tempword[lastpos] == '\'')
{
cout << "last position matches" << endl;
length = tempword.length(); //4
for(int k = 0; k < length; k++)
tempword[k] = tempword[k];//file
// Here again.
// What's this loop got to do?
// it copies the k-th character from tempword to the k-th character
// in tempword. No changes in tempword result from this.
//
words[i] = tempword;
}
else
{
cout << "no position matches" << endl;
words[i] = tempword;
}
}
}


--
Karl Heinz Buchegger
kb******@gascad.at
Jul 22 '05 #8

P: n/a
What should I use as a debugger? Basically I am just writing it in emacs
and compiling with g++.

"Karl Heinz Buchegger" <kb******@gascad.at> wrote in message
news:3F***************@gascad.at...


Rick wrote:

I got that, but I'm still not getting the desired output. Here is what
I have so far:
Devloping debug techniques is something you need to learn.
Just in case you don't have a debugger (which would simplify
things) why not insert some output statements at strategic
positions to enable yourself to watch what the program
is doing and why.

eg.

void convertarray(string words[], int count)
{
int lastpos;
string tempword;
int length;
bool yes;

for(int i = 0; i < count; i++)
{
tempword = words[i]; //file?
lastpos = tempword.length() - 1; //4


cout << "word is " << tempword << endl;
cout << "lastpos: " << lastpos << endl;
if(tempword[0] == '!' || tempword[0] == '(' || ')' || tempword[0]
== '"' || tempword[0] == '?' ||
tempword[0] == '.' || tempword[0] == ':' || tempword[0] == ';' || tempword[0] == ',' ||
tempword[0] == '\'')
{
cout << "first position matches" << endl;
length = tempword.length();


cout << "copying first" << length << " characters" << endl;
for(int j = 0; j < length + 1; j++)

{
cout << "copy " << tempword[j] << " (" << j << ") to position" << j <<

endl;
tempword[j] = tempword[j];

}
words[i] = tempword;


cout << "new word is " << tempword << endl;

// note: the above loop does .... nothing
// that means, of course it does something. It copies
// the j-th character to the j-th character. In the
// end tempword hasn't changed :-)
}
if(tempword[lastpos] == '!' || tempword[lastpos] == '(' ||
tempword[lastpos] == '"' ||
tempword[lastpos] == '?' || tempword[lastpos] == '.' ||
tempword[lastpos] == ';' ||
tempword[lastpos] == ',' || tempword[lastpos] == '\'')
{
cout << "last position matches" << endl;
length = tempword.length(); //4
for(int k = 0; k < length; k++)
tempword[k] = tempword[k];//file


// Here again.
// What's this loop got to do?
// it copies the k-th character from tempword to the k-th character
// in tempword. No changes in tempword result from this.
//
words[i] = tempword;
}
else
{
cout << "no position matches" << endl;
words[i] = tempword;
}
}
}


--
Karl Heinz Buchegger
kb******@gascad.at

Jul 22 '05 #9

This discussion thread is closed

Replies have been disabled for this discussion.