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why is casting malloc a bad thing?


I saw on a couple of recent posts people saying that casting the return
value of malloc is bad, like:

d=(double *) malloc(50*sizeo f(double));

why is this bad? I had always thought (perhaps mistakenly) that the
purpose of a void pointer was to cast into a legitimate date type. Is
this wrong? Why, and what is considered to be correct form?


Brian Blais

Nov 14 '05
231 23301
On 3 Feb 2004 12:21:35 -0800, ms*****@yahoo.c om (MSG) wrote:
Severian <se******@chlam ydia-is-not-a-flower.com> wrote in message news:<fd******* *************** **********@4ax. com>...
On Sun, 01 Feb 2004 01:29:35 GMT, CBFalconer <cb********@yah oo.com>
>Chris, I trust you are making suitable notes. Has anyone got a
>decent Ascii Art version of 'His Masters Voice'. The ineffable
>joy of sitting at the feet of the master!

Nice sig!

That was no sig, it was Ascii Art of ERT, the Trollmaster himself,
since I don't have one of 'His Master's Voice'.


Nov 14 '05 #231
On 26 Jan 2004 18:50:46 -0800, qe*@pobox.com (Paul Hsieh) wrote:
No, its a language weakness issue. One of the few good things to come
out of the C99 spec is the adoption of C++'s requirement for
prototype, and not assuming the default: int ()(int) . <snip>

C99 does not require prototype forms. It does (changed from C90)
require that functions be *declared* before use; that declaration may
be either prototype or old-style/K&R1; the former is preferable, but
not required. In C90 if you did not declare a function, it was
implicitly int ()() -- unspecified args, not one (of type) int.
- David.Thompson1 at worldnet.att.ne t
Nov 14 '05 #232

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