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using uint64_t with GCC


uint64_t i64_BitMask = (uint64_t) (1 << 33) - 1 ;
int a = (i64_BitMask >> 32);
printf ("BitMask %x\n", a);

This produces ffffffff. I'm pretty sure, watching the stages in
debugging, that 1 << 33 is resolving to zero, since it's being shifted
off the MSB of a 32 bit integer.

I am in general having problems with uint64_t with GCC. In particular,
I can't send one to printf and get a sensible output. The shift
operators appear to only work with 32-bit integers. Also, if I have
intermediate steps, it always seems to want to truncate the output to
32-bits. Putting in casts to uint64_t sometimes fixes it, but not
always. What do I do?

(using XCode, Apple's stdint.h)
Jul 23 '05 #1
4 12324
Richard Cavell wrote:

uint64_t i64_BitMask = (uint64_t) (1 << 33) - 1 ;

The problem is that the expression
(1 << 33)
is calculated (as it should) in integer mode, i.e. 32 bits.

The result (zero) is *THEN* cast to uint64_t.

Fix:

uint64_t i64_BitMask = (uint64_t) ((uint64_t)1 << 33) - 1 ;

jacob
Jul 23 '05 #2
jacob navia wrote:
=

uint64_t i64_BitMask = (uint64_t) ((uint64_t)1 << 33) - 1 ;


You have an unneeded cast there. The left-most cast serves no
purpose.
Jul 23 '05 #3
Ron Natalie wrote:
jacob navia wrote:
=

uint64_t i64_BitMask = (uint64_t) ((uint64_t)1 << 33) - 1 ;

You have an unneeded cast there. The left-most cast serves no
purpose.


True.

uint64_t i64_BitMask = ((uint64_t)1 << 33) - 1 ;

is better.

Also good is

uint64_t i64_BitMask = (1LL << 33) - 1 ;

jacob
Jul 23 '05 #4
i don't know why you need shifts, in some cases <bitset> is more
elegant IMHO

Jul 23 '05 #5

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