I have code how to print identity matrix but i want it to multiply by character L

[vj4u]

identity = new int[SS, SS];
            for (int row = 0; row < SS; row++)
            {
                for (int col = 0; col < SS; col++)
                {
                    identity[row, col] = (row == col) ? 1 : 0;
                    Response.Write(identity[row, col] + " ");
                }
                Response.Write("<br/>");
            }
 

the above code displays output suppose consider 3 x 3 matrix
it prints identity matrix as
1 0 0
0 1 0
0 0 1

i want to multiply it by L character so that the output must be
L 0 0
0 L 0
0 0 L

i have tried no.of ways but it is printing ASCII number of alphabet please help........

[Christian Binder]

Just mutiply the matrix' value by L.
L is int, 76 would be the ASCII number for 'L'
Or use Convert.ToInt32('L')

And when printing, convert value back to char by using Convert.ToChar(intValue);