How do I create a Stream object from a Bitmap

[Bill Fuller]

I have a need to write a Bitmap to a Stream, but get an error message on all
my attempts. I am doing something like the following:

Stream _appImage;

public frmCustomerFeedback(Bitmap bm)
{
InitializeComponent();

bm.Save(_appImage, System.Drawing.Imaging.ImageFormat.Jpeg); <== this
fails
//bm.Save("testimg.jpg", System.Drawing.Imaging.ImageFormat.Jpeg); <==
this works
ugPictureBox.Image = bm;
}

Any suggestions?

[Peter Duniho]

On Mon, 03 Nov 2008 16:33:27 -0800, Bill Fuller <so*****@nospam.comwrote:

I have a need to write a Bitmap to a Stream, but get an error message on
all
my attempts. I am doing something like the following:

Stream _appImage;

public frmCustomerFeedback(Bitmap bm)
{
InitializeComponent();

bm.Save(_appImage, System.Drawing.Imaging.ImageFormat.Jpeg); <==
this fails
//bm.Save("testimg.jpg", System.Drawing.Imaging.ImageFormat.Jpeg);
<== this works
ugPictureBox.Image = bm;
}

Any suggestions?

Yes. Initialize your _appImage variable so that it actually references an
instance of the Stream class.

Just as the documentation promises, if you pass "null" for that argument
(or the second, for that matter), you'll get an ArgumentNullException.

So: don't pass null. How can the method know what Stream to write to if
you don't pass it a valid reference to one?

Pete

[Bill Fuller]

Never mind... found my problem.

MemoryStream _appImage = new MemoryStream();
"Bill Fuller" <so*****@nospam.comwrote in message
news:%2****************@TK2MSFTNGP02.phx.gbl...

>I have a need to write a Bitmap to a Stream, but get an error message on
all my attempts. I am doing something like the following:

Stream _appImage;

public frmCustomerFeedback(Bitmap bm)
{
InitializeComponent();

bm.Save(_appImage, System.Drawing.Imaging.ImageFormat.Jpeg); <== this
fails
//bm.Save("testimg.jpg", System.Drawing.Imaging.ImageFormat.Jpeg); <==
this works
ugPictureBox.Image = bm;
}

Any suggestions?