I call method Foo(string s);
with Foo("foo"+"bar");
what's the deal here? 6 4424
On Oct 8, 4:20*pm, puzzlecracker <ironsel2...@gmail.comwrote:
I call method Foo(string s);
with Foo("foo"+"bar");
what's the deal here?
My guess is that you're doing something like:
string x = Foo("foo" + "bar");
If not, please show a short but complete program which demonstrates
the problem.
Jon
On Oct 8, 11:20 am, puzzlecracker <ironsel2...@gmail.comwrote:
I call method Foo(string s);
with Foo("foo"+"bar");
what's the deal here?
post your complete code
I do nt know if you are doing
string s = Foo("foo"+"bar");
or
Foo( Foo("foo"+"bar") );
On Oct 8, 11:20 am, puzzlecracker <ironsel2...@gmail.comwrote:
I call method Foo(string s);
with Foo("foo"+"bar");
what's the deal here?
In any case your method is returning void, it should be returning
string
On Oct 8, 11:22*am, "Jon Skeet [C# MVP]" <sk...@pobox.comwrote:
On Oct 8, 4:20*pm, puzzlecracker <ironsel2...@gmail.comwrote:
I call method Foo(string s);
with Foo("foo"+"bar");
what's the deal here?
My guess is that you're doing something like:
string x = Foo("foo" + "bar");
If not, please show a short but complete program which demonstrates
the problem.
Jon
I just call a method, with concatenation of two strings,that takes
string parameter. That's all.
BTW what is wrong with string x = Foo("foo" + "bar"); ?
On Oct 8, 8:43*am, puzzlecracker <ironsel2...@gmail.comwrote:
On Oct 8, 11:22*am, "Jon Skeet [C# MVP]" <sk...@pobox.comwrote:
On Oct 8, 4:20*pm, puzzlecracker <ironsel2...@gmail.comwrote:
I call method Foo(string s);
with Foo("foo"+"bar");
what's the deal here?
My guess is that you're doing something like:
string x = Foo("foo" + "bar");
If not, please show a short but complete program which demonstrates
the problem.
Jon
I just call a method, *with concatenation of two strings,that takes
string parameter. *That's all.
BTW what is wrong with *string x = Foo("foo" + "bar"); ?
can you please post the signature of method please?
I guess it is
public/private void Foo(string)
-Cnu
On Oct 8, 4:43*pm, puzzlecracker <ironsel2...@gmail.comwrote:
I just call a method, *with concatenation of two strings,that takes
string parameter. *That's all.
I'm afraid I don't believe you. Please post a short but complete
program that demonstrates the problem.
BTW what is wrong with *string x = Foo("foo" + "bar"); ?
If Foo is declared to be void, then you can't assign a string variable
based on the result, because there isn't one.
Jon This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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