Generate a Crystal Report with a Parameter

[Philluminati]

I have a crystal report which I need my application to generate. I can
do it like this:

ReportDocument thisReport = new ReportDocument();
thisReport.Load(inFilename);
thisReport.Refresh();
thisReport.ExportToDisk(ExportFormatType.PortableD ocFormat,outputFilename);
thisReport.Close();

This works perfectly. Now I have a crystal report that takes a
parameter called "FirewallId". I have tried to make the code like
this:

ReportDocument thisReport = new ReportDocument();
thisReport.Load(inFilename);
thisReport.SetParameterValue("FirewallId",25);
thisReport.Refresh();
thisReport.ExportToDisk(ExportFormatType.PortableD ocFormat,outputFilename);
thisReport.Close();

but I get missing parameter value. When I inspect "thisReports" fields
I am told there are two *more* parameters both called intid. Setting
them gives me errors - You cannot set parameters on linked fields and
not setting them gives me missing parameters error.

Can anyone help me please?

[Mel Weaver]

Try something like this, to see all the Parameter fields, and then just set
them

foreach (ParameterField field in thisReport.ParameterFields)
{
MessageBox.Show(field.Name);
thisReport.SetParameterValue(field.Name,"whateverv alue");
}

"Philluminati" <Ph*****************@gmail.comwrote in message
news:8c**********************************@m45g2000 hsb.googlegroups.com...

>I have a crystal report which I need my application to generate. I can
do it like this:

ReportDocument thisReport = new ReportDocument();
thisReport.Load(inFilename);
thisReport.Refresh();
thisReport.ExportToDisk(ExportFormatType.PortableD ocFormat,outputFilename);
thisReport.Close();

This works perfectly. Now I have a crystal report that takes a
parameter called "FirewallId". I have tried to make the code like
this:

ReportDocument thisReport = new ReportDocument();
thisReport.Load(inFilename);
thisReport.SetParameterValue("FirewallId",25);
thisReport.Refresh();
thisReport.ExportToDisk(ExportFormatType.PortableD ocFormat,outputFilename);
thisReport.Close();

but I get missing parameter value. When I inspect "thisReports" fields
I am told there are two *more* parameters both called intid. Setting
them gives me errors - You cannot set parameters on linked fields and
not setting them gives me missing parameters error.

Can anyone help me please?

[Ignacio Machin ( .NET/ C# MVP )]

On May 23, 7:54*am, Philluminati <[e-mail]>
wrote:

I have a crystal report which I need my application to generate. I can
do it like this:

ReportDocument thisReport = new ReportDocument();
thisReport.Load(inFilename);
thisReport.Refresh();
thisReport.ExportToDisk(ExportFormatType.PortableD ocFormat,outputFilename);
thisReport.Close();

This works perfectly. Now I have a crystal report that takes a
parameter called "FirewallId". I have tried to make the code like
this:

ReportDocument thisReport = new ReportDocument();
thisReport.Load(inFilename);
thisReport.SetParameterValue("FirewallId",25);
thisReport.Refresh();
thisReport.ExportToDisk(ExportFormatType.PortableD ocFormat,outputFilename);
thisReport.Close();

but I get missing parameter value. When I inspect "thisReports" fields
I am told there are two *more* parameters both called intid. Setting
them gives me errors - You cannot set parameters on linked fields and
not setting them gives me missing parameters error.

Can anyone help me please?

Hi,

you use ReportDocument.SetParameterValue()