Hi,
My application processes a file and updates the data into sql server.
The process takes around 30-90 seconds.I decided to put a timer to
display the user a label(making label visible false and true) with
message like "processing..." and do the other process using thread.
The timer won't works when the thread is started, so the label is not
displayed in the form
I have a label label1,a timer timer1 and command button in a form
timer1.interval=100;
private void timer1_Tick(object sender, System.EventArgs e)
{
label1.Visible = ! label1.Visible;
}
private void commandButton_Click(object sender, System.EventArgs e)
{
timer1.enabled=true;
label1.visible=true;
this.refresh
Thread t=new thread(new threadstart(updateMethod))
t.start()
timer1.enabled=false;
label1.visible=false
}
When I execute the above code label is not displayed in the
form.After the completion of thread only label get displayed.
Is there anything wrong in the above method of blinking a label?
Cheers,
Sony
8  3032 
You are disabling it too soon... when you disable the timer, I doubt
that updateMethod has even begun... you need to disable this at the end
of updateMethod instead, first jumping back onto the UI thread (due to
thread affinity):
void updateMethod() {
... your code
this.Invoke((MethodInvoker)delegate {
timer1.enabled=false;
label1.visible=false;
});
}
Marc
Ooh - just thought of a very useful extension method to Form:
public static void Invoke(this Form form, Action action) {
if(form == null) throw new ArgumentNullException("form");
if(action == null) throw new ArgumentNullException("action");
form.Invoke((Delegate)action);
}
Then you can use:
this.Invoke(delegate {...});
or
this.Invoke(() ={...});
Not a huge thing, but I like it ;-p
Marc
With Join you are simply hanging the UI; see my other post. And I don't
think Jon was suggesting posting that code - just something that
compiled and demonstrated the problem! You'd be amazed at how often we
get questions where the example code (because the OP hasn't tried it)
either doesn't show the same problem, or has even bigger issues [or just
doesn't compile].
Marc
(actually the target could have been Control or ISynchronizeInvoke)
I'm getting copiler errors
Which version of .NET are you using? 2.0 and above should be fine (if
you add a semicolon and fix the case that was copied verbatim from your
post). If you are using 1.1 (VS2003), then you need to do something
slightly different [I can't check if it compiles as I don't have 1.1 nearby]
Marc
void UpdateMethod()
{
//...
this.Invoke(new MethodInvoker(DisableTimer));
}
void DisableTimer()
{
timer1.Enabled = false;
label1.Visible = false;
}
Then there's the question of whether you're using C# 3 to start with...
Actually he cited the C# 2 version - so my guess is C# 1.2
(see, I did read the book!)
Marc
I have a label label1,a timer *timer1 and command button in a form
timer1.interval=100;
private void timer1_Tick(object sender, System.EventArgs e)
* * * * * * * * {
* * * * * * * * * * * * label1.Visible = ! label1.Visible;
* * * * * * * * }
Are you showing/hidding the label multiple times????
private void commandButton_Click(object sender, System.EventArgs e)
{
timer1.enabled=true;
label1.visible=true;
this.refresh
Thread t=new thread(new threadstart(updateMethod))
t.start()
timer1.enabled=false;
label1.visible=false
The last line of the above code is the line of the problem, you are
disabling the timer right there, most probably before it might even
tick for the first time.
You have to disable as the end of the worker method ( UpdateMethod)
On Apr 4, 3:45 pm, "Ignacio Machin ( .NET/ C# MVP )"
<ignacio.mac...@gmail.comwrote:
I have a label label1,a timer timer1 and command button in a form
timer1.interval=100;
private void timer1_Tick(object sender, System.EventArgs e)
{
label1.Visible = ! label1.Visible;
}
Are you showing/hidding the label multiple times????
private void commandButton_Click(object sender, System.EventArgs e)
{
timer1.enabled=true;
label1.visible=true;
this.refresh
Thread t=new thread(new threadstart(updateMethod))
t.start()
timer1.enabled=false;
label1.visible=false
The last line of the above code is the line of the problem, you are
disabling the timer right there, most probably before it might even
tick for the first time.
You have to disable as the end of the worker method ( UpdateMethod)
Yes showing/hidding the label multiple times
Cheers,
Sony This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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