DataGridView.CurrentCell (Set)

[Michel Walsh]

Someone has an example, C#, about how to set the cell(int row, int col) as
the current cell for a DataGridView. The example, in the help file, about
DataGrid.CurrentCell Property (Set)

myGrid.CurrentCell = new DataGridCell(1,1);
does not work, fro a DataGridView, since we cannot create a DataGridView
Cell while specifying only its row and column.
Vanderghast, Access MVP

[Michel Walsh]

Sorry for the bandwidth, just found that I just have to point to that said
cell, after all... doh. No need to 'create' one, as the example from
DataGrid leads us to think. The following works:
dataGridView1.CurrentCell = dataGridView1.Rows[iRow].Cells[iCol];


Vanderghast, Access MVP

"Michel Walsh" <va*************************@nospam.comwrote in message
news:0D**********************************@microsof t.com...

Someone has an example, C#, about how to set the cell(int row, int col)
as the current cell for a DataGridView. The example, in the help file,
about DataGrid.CurrentCell Property (Set)

myGrid.CurrentCell = new DataGridCell(1,1);
does not work, fro a DataGridView, since we cannot create a DataGridView
Cell while specifying only its row and column.
Vanderghast, Access MVP

[Nicholas Paldino [.NET/C# MVP]]

Michael,

There are more succinct ways of doing this:

dataGridView1.CurrentCellAddress = new Point(1, 1);

Or, if you wish:

dataGridView1.CurrentCell = dataGridView1[1, 1];

Both should have the same effect, although the top example will help
prevent unsharing of rows, which is good when you are using the grid in
virtual mode.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com

"Michel Walsh" <va*************************@nospam.comwrote in message
news:7F**********************************@microsof t.com...

Sorry for the bandwidth, just found that I just have to point to that said
cell, after all... doh. No need to 'create' one, as the example from
DataGrid leads us to think. The following works:
dataGridView1.CurrentCell = dataGridView1.Rows[iRow].Cells[iCol];


Vanderghast, Access MVP

"Michel Walsh" <va*************************@nospam.comwrote in message
news:0D**********************************@microsof t.com...

>Someone has an example, C#, about how to set the cell(int row, int col)
as the current cell for a DataGridView. The example, in the help file,
about DataGrid.CurrentCell Property (Set)

myGrid.CurrentCell = new DataGridCell(1,1);
does not work, fro a DataGridView, since we cannot create a DataGridView
Cell while specifying only its row and column.
Vanderghast, Access MVP

[Michel Walsh]

If I can ask you one more question.
While

dataGridView1.CurrentCell = dataGridView1[1, 1];

is fine for me, if I consider dataGridView[1,1] is a reference (a pointer)
to an existing cell, and then CurrentCell property just 'set the focus' on
that 'object reference' it got as its 'value', I fail to see how:
dataGridView1.CurrentCellAddress = new Point(1, 1);
could even work, since

new Point(1, 1)

is also a reference, but totally unrelated to any cell-references
(cell-pointers) owned by the dataGridView object. With this, in
consideration, can you explain the inner-working of
dataGridView1.CurrentCellAddress = new Point(1, 1);


Thanks for your time
Vanderghast, Access MVP

"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard.caspershouse.comwrote in
message news:C3**********************************@microsof t.com...

Michael,

There are more succinct ways of doing this:

dataGridView1.CurrentCellAddress = new Point(1, 1);

Or, if you wish:

dataGridView1.CurrentCell = dataGridView1[1, 1];

Both should have the same effect, although the top example will help
prevent unsharing of rows, which is good when you are using the grid in
virtual mode.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com

[Nicholas Paldino [.NET/C# MVP]]

Michel,

As you and Andrus pointed out, you the CurrentCellAddress property is
read-only, so you can't set it.

So only the first example I gave is valid.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com

"Michel Walsh" <vanderghast@VirusAreFunnierThanSpamwrote in message
news:uS**************@TK2MSFTNGP04.phx.gbl...

If I can ask you one more question.
While

dataGridView1.CurrentCell = dataGridView1[1, 1];

is fine for me, if I consider dataGridView[1,1] is a reference (a pointer)
to an existing cell, and then CurrentCell property just 'set the focus' on
that 'object reference' it got as its 'value', I fail to see how:
dataGridView1.CurrentCellAddress = new Point(1, 1);
could even work, since

new Point(1, 1)

is also a reference, but totally unrelated to any cell-references
(cell-pointers) owned by the dataGridView object. With this, in
consideration, can you explain the inner-working of
dataGridView1.CurrentCellAddress = new Point(1, 1);


Thanks for your time
Vanderghast, Access MVP

"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard.caspershouse.comwrote
in message news:C3**********************************@microsof t.com...

>Michael,

There are more succinct ways of doing this:

dataGridView1.CurrentCellAddress = new Point(1, 1);

Or, if you wish:

dataGridView1.CurrentCell = dataGridView1[1, 1];

Both should have the same effect, although the top example will help
prevent unsharing of rows, which is good when you are using the grid in
virtual mode.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com