help

[Reb]

Hi,
Could be a silly question.
I have 2 classes as written below.
how can i make the control tv (in WebForm1 class) to be
available in test class.
thanks
Reb

using System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Web;
using System.Web.SessionState;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.HtmlControls;
using Microsoft.Web.UI.WebControls;

namespace Treeview
{
Public class WebForm1 : System.Web.UI.Page
{
public Microsoft.Web.UI.WebControls.TreeView tv;

public void Page_Load(object sender, System.EventArgs e)
{
TreeNode root = new TreeNode();
root.Text = "Root";

TreeNode child1 = new TreeNode();
child1.Text = "Test";
root.Nodes.Add(child1);
tv.Nodes.Add(root);
}

#region Web Form Designer generated code
override protected void OnInit(EventArgs
e)
{
//
// CODEGEN: This call is required
by the ASP.NET Web Form Designer.
//
InitializeComponent();
base.OnInit(e);
}

/// <summary>
/// Required method for Designer support -
do not modify
/// the contents of this method with the
code editor.
/// </summary>
private void InitializeComponent()
{
this.Load += new
System.EventHandler(this.Page_Load);

}
#endregion
}

public class test
{
WebForm1 b = new WebForm1();
public string test1
{
}
}
}

[Michael Kremser]

Reb wrote:
^^^ Your full name would be nice :)

Could be a silly question.
There are no silly questions at all. ;-)
I have 2 classes as written below.
how can i make the control tv (in WebForm1 class) to be
available in test class.

Extend your test class by the following:

public class test
{
WebForm1 b = new WebForm1();

public Microsoft.Web.UI.WebControls.TreeView tv; // EXTEND!

public string test1
{
}
}

Now, in your code in WebForm1, just write:

test x = new test();
x.tv = this.tv;

HTH,

Michael

--
Michael Kremser
http://great.dynu.com/