Comparing ArrayLists

[=?Utf-8?B?Sm9zaFA=?=]

Hi All, I am attempting to compare values in two arraylists to make sure all
the values are the same. I am running into trouble with my code if both
arraylists compare okay up until a point and I am looping using the length of
the primary arraylist. For example:

oApproved (3 elements here):
[0]Red
[1]Green
[2]Yellow

oFound (5 elements here):
[0]Red
[1]Green
[2]Yellow
[3]Orange
[4]Blue

If using my loop below, the comparison will exit before it sees the last two
elements of arraylist 2 should not be there and should be removed.

for (indexI = 0; indexI <= oApproved.Count - 1; )
{
if (oFound[indexJ].ToString() ==
oApproved[indexI].ToString())
{
//TODO: remove debug
//RaiseVerificationEvent("Debug++File found: " +
oFound[indexJ].ToString());
//System.Diagnostics.Debug.WriteLine("File Approved:
" + oFound[indexJ].ToString());
indexI += 1;
indexJ += 1;
RaiseVerificationEvent(indexI.ToString() + " ------
" + indexJ.ToString());
}
else
{
CFileIO.DeleteFile(oFound[indexJ].ToString());
RaiseVerificationEvent("Unapproved file: " +
oFound[indexJ].ToString() + " deleted.");
//TODO: remove debug
System.Diagnostics.Debug.WriteLine("File Unapproved:
" + oFound[indexJ].ToString());
indexJ += 1;
}
}
I can see the flaw in my logic is the "for (indexI = 0; indexI <=
oApproved.Count - 1; )" because it will stop comparing when it reaches the
length of the primary ArrayList (in this case oApproved). Is there a better
way to compare arraylists? Or maybe a proven looping structure for comparing
arrays?

Thank You.

[Bill Butler]

"JoshP" <Jo***@discussions.microsoft.comwrote in message
news:F9**********************************@microsof t.com...

Hi All, I am attempting to compare values in two arraylists to make
sure all
the values are the same. I am running into trouble with my code if
both
arraylists compare okay up until a point and I am looping using the
length of
the primary arraylist. For example:

oApproved (3 elements here):
[0]Red
[1]Green
[2]Yellow

oFound (5 elements here):
[0]Red
[1]Green
[2]Yellow
[3]Orange
[4]Blue

If using my loop below, the comparison will exit before it sees the
last two
elements of arraylist 2 should not be there and should be removed.

<snip>

You could first check to see if the two Arrays are the same length.
If they are of different length they obviously are not the same.
Of course, if you allow duplicates in your lists then this will not
work.

Bill

[Chris Shepherd]

JoshP wrote:
[...]

oApproved (3 elements here):
[0]Red
[1]Green
[2]Yellow

oFound (5 elements here):
[0]Red
[1]Green
[2]Yellow
[3]Orange
[4]Blue

If using my loop below, the comparison will exit before it sees the last two
elements of arraylist 2 should not be there and should be removed.

[...]

I can see the flaw in my logic is the "for (indexI = 0; indexI <=
oApproved.Count - 1; )" because it will stop comparing when it reaches the
length of the primary ArrayList (in this case oApproved). Is there a better
way to compare arraylists? Or maybe a proven looping structure for comparing
arrays?

Well, this question is kind of vague.

If you're looking to ensure that the elements in oApproved exist in
oFound then you should use the Contains method to verify an element
exsists in the oFound list.

Chris.

[j1mb0jay]

Chris Shepherd wrote:

JoshP wrote:
[...]

>oApproved (3 elements here):
[0]Red
[1]Green
[2]Yellow

oFound (5 elements here):
[0]Red
[1]Green
[2]Yellow
[3]Orange
[4]Blue

If using my loop below, the comparison will exit before it sees the
last two elements of arraylist 2 should not be there and should be
removed.

[...]

>I can see the flaw in my logic is the "for (indexI = 0; indexI <=
oApproved.Count - 1; )" because it will stop comparing when it reaches
the length of the primary ArrayList (in this case oApproved). Is
there a better way to compare arraylists? Or maybe a proven looping
structure for comparing arrays?

Well, this question is kind of vague.

If you're looking to ensure that the elements in oApproved exist in
oFound then you should use the Contains method to verify an element
exsists in the oFound list.

Chris.

try looking at the big O theroy

j1mb0jay