magic code....

[vinnie]

When i execute the code, just the time to insert any number, and then
the window disapper. why?

namespace retry
{
public class Program
{
public static void Main(string[] args)
{
decimal number = 0;
InsertNumber(ref number);
Console.Write(" Number to be considerd: " + number);
Console.Read();
Show(number);
}
public static void InsertNumber(ref decimal number)
{
number = InsertNumber(" Value ");
}
public static decimal InsertNumber(string answer)
{
Console.WriteLine(" Insert the value of " + answer);
string accept = Console.ReadLine();
decimal value = Convert.ToDecimal(accept);
return value;
}
public static void Show(decimal number)
{
for (int amount = 0; amount >= number; amount++)
{
number = (number + 1);
Console.WriteLine(number);
Console.Read();

}
}
}
}

[Mark Peters]

On Sep 3, 8:20 pm, vinnie <[e-mail]:

When i execute the code, just the time to insert any number, and then
the window disapper. why?

for (int amount = 0; amount >= number; amount++)

if number is positive, Show() does nothing. Flip your comparison?

[vinnie]

On Sep 3, 9:03 pm, Mark Peters <[e-mail]:

>

for (int amount = 0; amount >= number; amount++)

if number is positive, Show() does nothing. Flip your comparison?

i did, and it happens this: if for example i put 10, i get:
9
8

but then all stops. If i push again enter, i get the same:

7
6
and so on... why?

[=?Utf-8?B?TW9kZWxCdWlsZGVy?=]

I believe you get two values written per loop, since your reading one byte
from the console (read, rather than readline). When you hit enter, this is
two bytes. Change it to a readline and you get one value at a time.

It's hard telling from the code what you really want to get however...
"vinnie" wrote:

On Sep 3, 9:03 pm, Mark Peters <[e-mail]:

>for (int amount = 0; amount >= number; amount++)

if number is positive, Show() does nothing. Flip your comparison?

i did, and it happens this: if for example i put 10, i get:
9
8

but then all stops. If i push again enter, i get the same:

7
6
and so on... why?

[vinnie]

On Sep 3, 10:38 pm, ModelBuilder
<[e-mail]:

I believe you get two values written per loop, since your reading one byte
from the console (read, rather than readline). When you hit enter, this is
two bytes. Change it to a readline and you get one value at a time.

It's hard telling from the code what you really want to get however...

What i wish to realize is this: that once i have inserted the number,
i see the list of the operation, something like this (let's say that
the number is 8):
7
6
5
4
3
2

[=?Utf-8?B?TW9kZWxCdWlsZGVy?=]

In that case, you probably don't need the console.read inside the loop at all.

"vinnie" wrote:

On Sep 3, 10:38 pm, ModelBuilder
<[e-mail]:

I believe you get two values written per loop, since your reading one byte
from the console (read, rather than readline). When you hit enter, this is
two bytes. Change it to a readline and you get one value at a time.

It's hard telling from the code what you really want to get however...

What i wish to realize is this: that once i have inserted the number,
i see the list of the operation, something like this (let's say that
the number is 8):
7
6
5
4
3
2

[=?Utf-8?B?UGV0ZXIgQnJvbWJlcmcgW0MjIE1WUF0=?=]

Replace Console.Read() with Console.ReadLine() and the window won't disappear
until you press the Enter key to signify the end of a line of input.
-- Peter
Recursion: see Recursion
site: http://www.eggheadcafe.com
unBlog: http://petesbloggerama.blogspot.com
BlogMetaFinder: http://www.blogmetafinder.com

"vinnie" wrote:

When i execute the code, just the time to insert any number, and then
the window disapper. why?

namespace retry
{
public class Program
{
public static void Main(string[] args)
{
decimal number = 0;
InsertNumber(ref number);
Console.Write(" Number to be considerd: " + number);
Console.Read();
Show(number);
}
public static void InsertNumber(ref decimal number)
{
number = InsertNumber(" Value ");
}
public static decimal InsertNumber(string answer)
{
Console.WriteLine(" Insert the value of " + answer);
string accept = Console.ReadLine();
decimal value = Convert.ToDecimal(accept);
return value;
}
public static void Show(decimal number)
{
for (int amount = 0; amount >= number; amount++)
{
number = (number + 1);
Console.WriteLine(number);
Console.Read();

}
}
}
}

[Ignacio Machin \( .NET/ C# MVP \)]

Hi,

When a console program ends the console is closed, this is what is
happening, put a ReadLine() if you want the cosole to stick around

"vinnie" <ce**********@gmail.comwrote in message
news:11**********************@57g2000hsv.googlegro ups.com...

When i execute the code, just the time to insert any number, and then
the window disapper. why?

namespace retry
{
public class Program
{
public static void Main(string[] args)
{
decimal number = 0;
InsertNumber(ref number);
Console.Write(" Number to be considerd: " + number);
Console.Read();
Show(number);
}
public static void InsertNumber(ref decimal number)
{
number = InsertNumber(" Value ");
}
public static decimal InsertNumber(string answer)
{
Console.WriteLine(" Insert the value of " + answer);
string accept = Console.ReadLine();
decimal value = Convert.ToDecimal(accept);
return value;
}
public static void Show(decimal number)
{
for (int amount = 0; amount >= number; amount++)
{
number = (number + 1);
Console.WriteLine(number);
Console.Read();

}
}
}
}