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Regular express question

I have the following words, and I want to extract the first part and the
trailing numbers.

OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null

I have the following regular express:
(?<first>.*?)(?<second>\d+)
This one works well for the given first two examples but not the third one.

And (?<first>.*?)(?<second>\d+)$ returns strange result.

Jul 16 '07 #1
5 1998
I'm unfamiliar with the <first<secondsyntax you're using, but the
following regular expression works for the three samples given:

Regex.Replace("OP001", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "OP, 001"
Regex.Replace("ST02", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "CD, 02"
Regex.Replace("00A", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussions.microsoft.comwrote in message
news:FC**********************************@microsof t.com...
>I have the following words, and I want to extract the first part and the
trailing numbers.

OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null

I have the following regular express:
(?<first>.*?)(?<second>\d+)
This one works well for the given first two examples but not the third
one.

And (?<first>.*?)(?<second>\d+)$ returns strange result.
Jul 16 '07 #2
I am using match.Groups.

"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsyntax you're using, but the
following regular expression works for the three samples given:

Regex.Replace("OP001", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "OP, 001"
Regex.Replace("ST02", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "CD, 02"
Regex.Replace("00A", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussions.microsoft.comwrote in message
news:FC**********************************@microsof t.com...
I have the following words, and I want to extract the first part and the
trailing numbers.

OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null

I have the following regular express:
(?<first>.*?)(?<second>\d+)
This one works well for the given first two examples but not the third
one.

And (?<first>.*?)(?<second>\d+)$ returns strange result.

Jul 16 '07 #3
Yes, it works. Thanks.

However, there is another match, for a number

123 =123, null

how to add this one to the regular express?

"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsyntax you're using, but the
following regular expression works for the three samples given:

Regex.Replace("OP001", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "OP, 001"
Regex.Replace("ST02", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "CD, 02"
Regex.Replace("00A", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussions.microsoft.comwrote in message
news:FC**********************************@microsof t.com...
I have the following words, and I want to extract the first part and the
trailing numbers.

OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null

I have the following regular express:
(?<first>.*?)(?<second>\d+)
This one works well for the given first two examples but not the third
one.

And (?<first>.*?)(?<second>\d+)$ returns strange result.

Jul 17 '07 #4
Sorry, should be

123 =null, 123

"Matt" wrote:
Yes, it works. Thanks.

However, there is another match, for a number

123 =123, null

how to add this one to the regular express?

"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsyntax you're using, but the
following regular expression works for the three samples given:

Regex.Replace("OP001", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "OP, 001"
Regex.Replace("ST02", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "CD, 02"
Regex.Replace("00A", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussions.microsoft.comwrote in message
news:FC**********************************@microsof t.com...
>I have the following words, and I want to extract the first part and the
trailing numbers.
>
OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null
>
I have the following regular express:
(?<first>.*?)(?<second>\d+)
This one works well for the given first two examples but not the third
one.
>
And (?<first>.*?)(?<second>\d+)$ returns strange result.
>
Jul 17 '07 #5
Try something like this (not tested):

(.*\D+)?(\d*)
"Matt" <Ma**@discussions.microsoft.comwrote in message
news:AB**********************************@microsof t.com...
Sorry, should be

123 =null, 123

"Matt" wrote:
>Yes, it works. Thanks.

However, there is another match, for a number

123 =123, null

how to add this one to the regular express?

"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsyntax you're using, but the
following regular expression works for the three samples given:

Regex.Replace("OP001", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "OP,
001"
Regex.Replace("ST02", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "CD, 02"
Regex.Replace("00A", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussions.microsoft.comwrote in message
news:FC**********************************@microsof t.com...
I have the following words, and I want to extract the first part and
the
trailing numbers.

OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null

I have the following regular express:
(?<first>.*?)(?<second>\d+)
This one works well for the given first two examples but not the
third
one.

And (?<first>.*?)(?<second>\d+)$ returns strange result.
Jul 17 '07 #6

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