Hi Fletch,
I'm betting the problem is Random rand = new Random(); It takes the
randomized seed from a timestamp, but if you use the same seed later you
will get the same sequence of numbers. Since you initialize rand at each
turn the timestamp will not have time to change, effectively causing rand
to be seeded with the same number at each turn. You probably see only one
cell get a number since x, y and r will get the same each time. When you
use a breakpoint, you give the timestamp plenty of time to change, giving
you a new seed the next turn.
Move the initialization of rand outside the loop to fix this.
Random rand = new Random();
for (int c = 0; c < 6; c++)
{
int x = rand.Next(0, 9);
int y = rand.Next(0, 9);
int r = rand.Next(1, 9);
board[x, y] = r;
}
On Fri, 16 Feb 2007 06:48:22 +0100, fletch <fl*****@yahoo.comwrote:
I'm trying to write a little sudoku game. When i try to set a board i
use a for loop.
Here it is
for (int c = 0; c < 6; c++)
{
Random rand = new Random();
int x = rand.Next(0, 9);
int y = rand.Next(0, 9);
int r = rand.Next(1, 9);
board[x, y] = r;
}
but for some reason it only runs once unless i put a break point
anywhere in it.
When there's a breakpoint in it it works fine though. Anyone got any
ideas to why?
--
Happy Coding!
Morten Wennevik [C# MVP]
