I can't get the value of an attribute in an xml file

[roto23]

I am able to correctly XPath to the correct Node in the XML file,
however when I try to get the value of an attribute on that node, it
doenot work.

intX gets a value of 1 so I am sure the XPath query is correct but this
line retunrs an empty string...
strDBFactor = NodeIter.Current.GetAttribute("DeathBenefitFactor" , "");

here is the complete code..

string strDBFactor;
int intX;
strXmlQuery = "Root/DataPoint[@Age='40' and @RateClass='P' and
@Sex='F']";
docNav = new XPathDocument(strXmlFileNameAndPath);
nav = docNav.CreateNavigator();
NodeIter = nav.Select(strXmlQuery);
intX = NodeIter.Count;
strDBFactor = NodeIter.Current.GetAttribute("DeathBenefitFactor" , "");
return strDBFactor;

[Jon Skeet [C# MVP]]

<ro****@earthlink.netwrote:

I am able to correctly XPath to the correct Node in the XML file,
however when I try to get the value of an attribute on that node, it
doenot work.

intX gets a value of 1 so I am sure the XPath query is correct but this
line retunrs an empty string...
strDBFactor = NodeIter.Current.GetAttribute("DeathBenefitFactor" , "");

here is the complete code..

string strDBFactor;
int intX;
strXmlQuery = "Root/DataPoint[@Age='40' and @RateClass='P' and
@Sex='F']";
docNav = new XPathDocument(strXmlFileNameAndPath);
nav = docNav.CreateNavigator();
NodeIter = nav.Select(strXmlQuery);
intX = NodeIter.Count;
strDBFactor = NodeIter.Current.GetAttribute("DeathBenefitFactor" , "");
return strDBFactor;

Could you post a short but complete program which demonstrates the
problem?

See http://www.pobox.com/~skeet/csharp/complete.html for details of
what I mean by that.

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

[roto23]

Thanks for trying, but I got it working using this method..
private System.Xml.XmlDocument objXmlDoc;
private System.Xml.XmlNode objXmlNode;

public string SolveFordeathBenefit()
{
string strDBFactor;

objXmlDoc = new XmlDocument();
objXmlDoc.Load(strXmlFileNameAndPath);
strXmlQuery = "Root/DataPoint[@Age='40' and @RateClass='P' and
@Sex='F']";
objXmlNode = objXmlDoc.SelectSingleNode(strXmlQuery);
strDBFactor =
objXmlNode.Attributes.GetNamedItem("DeathBenefitFa ctor").Value;
return strDBFactor;
]