short res = shortA + shortB result in compiler error. Why?

[nyhetsgrupper]

The following code result in the following compilation error: Error 1
Cannot implicitly convert type 'int' to 'short'. An explicit conversion
exists (are you missing a cast?)

short a = 1;
short b = 2;
short result = a + b;

Can anyone explain why??

[Diogene Laerzio]

1 e 2 sono int. Prova con:

short a = (short) 1;
short b = (short) 2;
short result = a + b;
ny***********@gmail.com ha scritto:

The following code result in the following compilation error: Error 1
Cannot implicitly convert type 'int' to 'short'. An explicit conversion
exists (are you missing a cast?)

short a = 1;
short b = 2;
short result = a + b;

Can anyone explain why??

[Diogene Laerzio]

ny***********@gmail.com ha scritto:

The following code result in the following compilation error: Error 1
Cannot implicitly convert type 'int' to 'short'. An explicit conversion
exists (are you missing a cast?)

short a = 1;
short b = 2;
short result = a + b;

Can anyone explain why??

[Diogene Laerzio]

1 e 2 sono interi. Prova con:

short a = (short) 1;
short b = (short) 2;
short result = a + b;

Funziona?

ny***********@gmail.com ha scritto:

The following code result in the following compilation error: Error 1
Cannot implicitly convert type 'int' to 'short'. An explicit conversion
exists (are you missing a cast?)

short a = 1;
short b = 2;
short result = a + b;

Can anyone explain why??

[Bobbo]

ny***********@gmail.com wrote:

The following code result in the following compilation error: Error 1
Cannot implicitly convert type 'int' to 'short'. An explicit conversion
exists (are you missing a cast?)

You can either use fully grown int's, or do this:
short result = (short)(a + b);

This article explains what's going on:
http://msdn.microsoft.com/library/de...vclrfShort.asp

[Diogene Laerzio]

1 e 2 are integers. Try:

short a = (short) 1;
short b = (short) 2;
short result = a + b;
OK?

ny***********@gmail.com ha scritto:

The following code result in the following compilation error: Error 1
Cannot implicitly convert type 'int' to 'short'. An explicit conversion
exists (are you missing a cast?)

short a = 1;
short b = 2;
short result = a + b;

Can anyone explain why??

[Bobbo]

Diogene Laerzio wrote:

1 e 2 are integers. Try:

short a = (short) 1;
short b = (short) 2;
short result = a + b;

That doesn't work in my version (2005) because it's the result of the
addition that is an int, not the internal value of a and b.

[Jon Skeet [C# MVP]]

Diogene Laerzio wrote:

1 e 2 are integers. Try:

short a = (short) 1;
short b = (short) 2;
short result = a + b;

The first two lines were fine before - the compile can tell they're
numeric literals.

The issue is that there's no short operator+ (short, short) - only int
operator+ (int, int).

Basically, the OP needs to cast the result:

short a = 1;
short b = 2;
short result = (short) (a+b);

Jon

[Diogene Laerzio]

I was searching a way to overload the plus operator but I couldn't find
it. Is it possible to define a:

"short operator+ (short, short)" ?

or to redefine:

"int operator+ (int, int)" ?

Jon Skeet [C# MVP] ha scritto:

Diogene Laerzio wrote:

1 e 2 are integers. Try:

short a = (short) 1;
short b = (short) 2;
short result = a + b;

The first two lines were fine before - the compile can tell they're
numeric literals.

The issue is that there's no short operator+ (short, short) - only int
operator+ (int, int).

Basically, the OP needs to cast the result:

short a = 1;
short b = 2;
short result = (short) (a+b);

Jon

[Jonny Jack]

The plus operator implicitly up casts the shorts to ints and generates an int
result which can't be implicitly down cast back o a short. So you need to
explicitly cast the sum (short)(a+b). This is like telling the compiler "I
know what I'm doing and it is OK, trust me.".

--
Thanks
Jonny
"ny***********@gmail.com" wrote:

The following code result in the following compilation error: Error 1
Cannot implicitly convert type 'int' to 'short'. An explicit conversion
exists (are you missing a cast?)

short a = 1;
short b = 2;
short result = a + b;

Can anyone explain why??

[Jon Skeet [C# MVP]]

Diogene Laerzio <di*************@gmail.comwrote:

I was searching a way to overload the plus operator but I couldn't find
it. Is it possible to define a:

"short operator+ (short, short)" ?

or to redefine:

"int operator+ (int, int)" ?

No. You could write your own utility method:

public static short Add (short x, short y)
{
return (short) (x+y);
}

but I think it would be more effort than just including the casts, to
be honest.

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too