In article <11**********************@k70g2000cwa.googlegroups .com>,
sherifffruitfly <sh*************@gmail.comwrote:
: I have a file that is full of lines fitting this pattern:
:
: (?<year>\d{4}),(?<amount>\d{6,7})
:
: I'm likely to get a bunch of hits with this - I'm only interested in
: the *last* one. Is there a way to build the concept "last" into the
: regex itself? Or is taking the last element of the match array the only
: thing to do?
:
: I would just prefer to avoid have a potentially long array being sent
: around...
Start your pattern with .* to grab the last match. For example:
using System;
using System.Text.RegularExpressions;
namespace consapp
{
class Program
{
static void Main(string[] args)
{
const string pattern = @"(?<year>\d{4}),(?<amount>\d{6,7})";
Regex regex;
Match m;
string input = "1234,1234569999,123456";
Console.WriteLine("Vanilla pattern:");
regex = new Regex(pattern);
m = regex.Match(input);
Console.WriteLine(" - year=[{0}], amount={1}",
m.Groups["year"], m.Groups["amount"]);
Console.WriteLine("Leading dot-star:");
regex = new Regex(".*" + pattern);
m = regex.Match(input);
Console.WriteLine(" - year=[{0}], amount={1}",
m.Groups["year"], m.Groups["amount"]);
}
}
}
Output:
Vanilla pattern:
- year=[1234], amount=1234569
Leading dot-star:
- year=[9999], amount=123456
Hope this helps,
Greg
--
Criminal means, once tolerated, are soon preferred.
-- Edmund Burke
