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how to make sure this.Test() call base class method in base class constructor

Hi,

There is a method Test() implemented in base class and override in subclass.

In base class itself, how to make sure

this.Test() will just call implementation in base class only?

Thanks a lot!
Ryan Liu
Aug 27 '06 #1
2 1629
Ryan,
>In base class itself, how to make sure

this.Test() will just call implementation in base class only?
You can't, that would defeat the purpose of virtual methods. Instead
you can move the base class' implementation of the Test method to
another, not-virtual method (say TestImpl). Call TestImpl from from
Test and call TestImpl directly if you want non-virtual behaviour.
Mattias

--
Mattias Sjögren [C# MVP] mattias @ mvps.org
http://www.msjogren.net/dotnet/ | http://www.dotnetinterop.com
Please reply only to the newsgroup.
Aug 27 '06 #2
Ryan Liu wrote:
There is a method Test() implemented in base class and override in subclass.

In base class itself, how to make sure

this.Test() will just call implementation in base class only?
You can not force an implementation in a subclass.

But you can omit the virtual keyword, so they can not
override.

Arne
Aug 27 '06 #3

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