Can't convert string to double!

[zelyal]

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

[Jon Skeet [C# MVP]]

zelyal wrote:

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

Almost certainly you're using the wrong CultureInfo. Try specifying
CultureInfo.InvariantCulture to parse in - I suspect it's currently
assuming that "." is a thousands separator rather than a decimal point.

Jon

[Nicholas Paldino [.NET/C# MVP]]

zelyal,

Works for me. Are you sure it is this line of code?
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com

"zelyal" <ze****@discussions.microsoft.com> wrote in message
news:5C**********************************@microsof t.com...

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

[Marc Gravell]

culture, perhaps?

[Kevin Spencer]

What version of the framework are you using? I copied your line of code to a
..Net 2.0 project and it ran without exceptions.

--
HTH,

Kevin Spencer
Microsoft MVP
Professional Development Numbskull

Abnormality is anything but average.

"zelyal" <ze****@discussions.microsoft.com> wrote in message
news:5C**********************************@microsof t.com...

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

[Göran Andersson]

Specify the number format or culture to use. If you don't do that, you
are using the number format of the default culture.

double v1 = Double.Parse("7200.0", CultureInfo.InvariantCulture);

zelyal wrote:

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

[Claes Bergefall]

Verify that the decimal separator is '.' and not something else (like ','
for example). You can use the
System.Globalization.NumberFormatInfo.CurrentInfo. NumberDecimalSeparator
property to check it in code

/claes

"zelyal" <ze****@discussions.microsoft.com> wrote in message
news:5C**********************************@microsof t.com...

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

[Mark Rae]

"zelyal" <ze****@discussions.microsoft.com> wrote in message
news:5C**********************************@microsof t.com...

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

Culture, I suspsect. Are you in a country which doesn't use "." as its
decimal separator...?

[zelyal]

The problem is in separator. Dot sign leads to error, but with comma sign
all OK.
I tried:
double v1 = Double.Parse ("7200.0", NumberStyles.Float);
but it didn't help. And
v1 = Double.Parse("7200.00", CultureInfo.InvariantCulture);
is gone OK.
Thank to all and specially to Göran Andersson !
Alexey

[John Fullmer]

A clean way to handle this kind of situation is the Double.TryParse().

~ John Fullmer
zelyal wrote:

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?

[Göran Andersson]

That prevents the code from causing an exception, but it doesn't solve
the actual problem, which is the number format used to parse the string.
John Fullmer wrote:

A clean way to handle this kind of situation is the Double.TryParse().

~ John Fullmer
zelyal wrote:

I got :
An unhandled exception of type 'System.FormatException' occurred in
mscorlib.dll

Additional information: Input string was not in a correct format.

at execution of simple line:
double v1 = Double.Parse ("7200.0");

What's wrong?