Hi John,

bit shifting is modifying the bits in binary so you are talking about

base2, if you want to preserve the numbers after you combine them ie 12345 is

in base10 then you want to multiply to the power of 10 to shift the whole

number left. You also need to make sure that you have a datatype that is

capable of representing this large number. What you want to do is:

12321

34543

67876

i'd like to end up with

123213454367876

then it is:

123210000000000 + 3454300000 + 67876 = 123213454367876

which you could do by:

int i1 = 12321;

int i2 = 34543;

int i3 = 67876;

double dall = i1 * 1E10 + i2 * 1E5 + i3;

Hope that helps

Mark Dawson

http://www.markdawson.org

"john conwell" wrote:

I have 3 5-digit numbers that i'd like to combine into one 15 digit number,

and later rip back into the original 3 5-digit numbers.

I know i can do this easily with some string manipulations, but i'm pretty

sure i can do the same thing with some bitwise operation like bit shifting or

something.

basically, if i have the following 3 numbesr

12321

34543

67876

i'd like to end up with

123213454367876

any ideas?