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OpenFileDialog Initial Directory not working

I'm a bit confused by this - when I set the InitialDiretory of an
OpenFileDialog to be a subfolder within the same folder as the app, the
file dialog does not initially display the folder - instead it shows
the last used folder (this persists after closing the app).

However, if I use a different path (e.g. "C:\\") then every time the
dialog is shown, it starts at the correct directory every time.

Is there something special about an app path that a file dialog doesn't
like, or is my syntax wrong???

OpenFileDialog objOpenDlg = new OpenFileDialog();
objOpenDlg.InitialDirectory = Application.ExecutablePath + @"\Games\";
if (objOpenDlg.ShowDialog() == DialogResult.OK)
//do some stuff here

It doesn't seem to make any difference whether the app is a debug or
release mode, and whether it is run from the IDE or not.

Any thoughts???


Dec 16 '05 #1
2 7654
Hi Greg,

Use Application.StartupPath instead. Application.ExecutablePath
includes the file name.

objOpenDlg.InitialDirectory = Path.Combine(Application.StartupPath,


Dec 16 '05 #2
Excellent, thanks a lot!

Dec 16 '05 #3

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