Reflection.Emit and generic methods

[ayende]

How do I use Reflection.Emit to produce code similar to this?

public void bar<T>()
{
}
public void foo<J>()
{
bar<J>();
}

More specifically, I don't know how to bind the method call using
Reflection.Emit.
Any suggestions?

The IL that is generated is:

..method public hidebysig instance void foo<J>() cil managed
{
// Code Size: 9 byte(s)
.maxstack 8
L_0000: nop
L_0001: ldarg.0
L_0002: call instance void dempo::bar<!!0>()
L_0007: nop
L_0008: ret
}

But I don't see a way to get the !!0 from Reflection.Emit.

[Daniel O'Connell [C# MVP]]

<ay****@gmail.com> wrote in message
news:11*********************@g43g2000cwa.googlegro ups.com...

How do I use Reflection.Emit to produce code similar to this?

public void bar<T>()
{
}
public void foo<J>()
{
bar<J>();
}

More specifically, I don't know how to bind the method call using
Reflection.Emit.
Any suggestions?

Look at the MakeGenericMethod method on MethodInfo. It should allow you to
bind to the method you want to call with the type parameters you want.

[ayende]

I looked at them, but that isn't the problem, I have the method info
for bar, I just don't know what to pass to make generic method?

From foo(), how do I get what J is?

[Daniel O'Connell [C# MVP]]

<ay****@gmail.com> wrote in message
news:11*********************@f14g2000cwb.googlegro ups.com...

I looked at them, but that isn't the problem, I have the method info
for bar, I just don't know what to pass to make generic method?

From foo(), how do I get what J is?

Ahh, I see what you mean now. Try using the GetGenericArguments method, that
should return an array of types which will represent the generic arguments
for hte method.