MdiParent and InvokeMember...

[Robert Vasquez]

How can I get a form in a class library to become an MDI Child of the main
application? I've tried the following, but does not work:

Class Library...
public class Class1
{
public Class1()
{
//
// TODO: Add constructor logic here
//
}
public static bool
DisplayForm(System.Windows.Forms.Form theMDIParent)
{
Form1 f = new Form1();
f.MdiParent = theMDIParent;
f.ShowDialog();
f.Close();
return true;
}
}

In Main App...
Assembly asm = Assembly.LoadFile(@"c:\Documents and Settings\rvasquez\My
Documents\Visual Studio
Projects\TestMDIForms\OtherForms\bin\debug\OtherFo rms.dll");
Type t = asm.GetType("OtherForms.Class1");
object result = null;
object[] arguments = {this};
result = t.InvokeMember("DisplayForm",BindingFlags.InvokeMe thod, null,
result, arguments);

[Martin Stainsby]

possibly setting f.TopLevel = false; may be neccesary, it is when immitating
mdi on a normal form. Also and also guessing it mght be neccesary to set the
mdiclient as the parent rather than setting mdiparent. I did a immitation
mdi app that needed this behaviour to get a form to act as a child form,
whether it works with a proper mdi app I can only guess at.

Hope something is useful.

Martin.

"Robert Vasquez" <Ro***********@discussions.microsoft.com> wrote in message
news:8E**********************************@microsof t.com...

How can I get a form in a class library to become an MDI Child of the main
application? I've tried the following, but does not work:

Class Library...
public class Class1
{
public Class1()
{
//
// TODO: Add constructor logic here
//
}
public static bool
DisplayForm(System.Windows.Forms.Form theMDIParent)
{
Form1 f = new Form1();
f.MdiParent = theMDIParent;
f.ShowDialog();
f.Close();
return true;
}
}

In Main App...
Assembly asm = Assembly.LoadFile(@"c:\Documents and Settings\rvasquez\My
Documents\Visual Studio
Projects\TestMDIForms\OtherForms\bin\debug\OtherFo rms.dll");
Type t = asm.GetType("OtherForms.Class1");
object result = null;
object[] arguments = {this};
result = t.InvokeMember("DisplayForm",BindingFlags.InvokeMe thod, null,
result, arguments);

[Robert Vasquez]

Martin, thank you for your reply. I found out my mistake to be the
following...

f.ShowDialog();

instead of...

f.Show();

"Martin Stainsby" wrote:

possibly setting f.TopLevel = false; may be neccesary, it is when immitating
mdi on a normal form. Also and also guessing it mght be neccesary to set the
mdiclient as the parent rather than setting mdiparent. I did a immitation
mdi app that needed this behaviour to get a form to act as a child form,
whether it works with a proper mdi app I can only guess at.

Hope something is useful.

Martin.

"Robert Vasquez" <Ro***********@discussions.microsoft.com> wrote in message
news:8E**********************************@microsof t.com...

How can I get a form in a class library to become an MDI Child of the main
application? I've tried the following, but does not work:

Class Library...
public class Class1
{
public Class1()
{
//
// TODO: Add constructor logic here
//
}
public static bool
DisplayForm(System.Windows.Forms.Form theMDIParent)
{
Form1 f = new Form1();
f.MdiParent = theMDIParent;
f.ShowDialog();
f.Close();
return true;
}
}

In Main App...
Assembly asm = Assembly.LoadFile(@"c:\Documents and Settings\rvasquez\My
Documents\Visual Studio
Projects\TestMDIForms\OtherForms\bin\debug\OtherFo rms.dll");
Type t = asm.GetType("OtherForms.Class1");
object result = null;
object[] arguments = {this};
result = t.InvokeMember("DisplayForm",BindingFlags.InvokeMe thod, null,
result, arguments);